All categories

2 years ago

A solution with a molarity of 0.1850 contains 19.30 grams of BaCl2. What is the volume of the solution

Chemistry

1 answer:

svetlana [45]2 years ago

4 0

Answer:

Volume in L = 0.50 L

Explanation:

Given data:

Molarity of solution = 0.1850 M

Mass of BaCl₂ = 19.30 g

Volume of solution = ?

Solution:

First of all we will calculate the number of moles of solute:

Number of moles = mass/molar mass

Molar mass of BaCl₂ = 208.23 g/mol

Number of moles = 19.30 g / 208.23 g/mol

Number of moles = 0.093 mol

Volume of solution:

Molarity = number of moles of solute / volume of solution in L

0.1850 M = 0.093 mol / Volume in L

Volume in L = 0.093 mol / 0.1850 M (M= mol/L)

Volume in L = 0.50 L

You might be interested in

Suppose that coal of density 1.5 g/cm^3 is pure carbon. (It is, in fact, much more complicated, but this is a reasonable first a

NISA [10]

Answer:

q = -6464.9 kJ

Explanation:

We are given that the heat of combustion is ∆H° = −394 kJ per mol of carbon.Therefore what we need to do is calculate how many moles of C are in the lump of coal by finding its mass since the density is given.

vol = 5.6 cm x 5.1 cm x 4.6 cm = 131.38 cm³

m = d x v = 1.5 g/cm³ x 131.38 cm³ = 197.06 g

mol C = m/MW = 197.06 g/ 12.01g/mol = 16.41 mol

q = −394 kJ /mol C x 16.41 mol C = -6464.9 kJ

7 0

3 years ago

Radio waves travel at the speed of light which is 3.00 x 10^8. How many minutes does it take for a radio message to reach saturn

ryzh [129]

Answer:

43.89 min

Explanation:

Given that:-

The speed of light = $3.00\times 10^8\ m/s$

The distance = $7.9\times 10^8\ km$

The conversion of distance in km to distance into m is shown below as:-

1 km = 1000 m

So,

Distance = $7.9\times 10^8\times 1000\ m=7.9\times 10^{11}\ m$

The relation between speed distance and time is shown below as:-

$Speed=\frac{Distance}{Time}$

Thus,

$3.00\times 10^8=\frac{7.9\times 10^{11}}{Time}$

$300000000\times time=10^{11}\times \:7.9\ s$

Time = 2633.33 seconds

Also, 1 s = 1/60 min

So,

Time= $\frac{2633.33}{60}\ min=43.89\ min$

3 0

3 years ago

A 25.0 mL sample of sulfuric acid is completely neutralized by adding 32.8 mL of 0.116 mol/L ammonia solution. Ammonium sulfate

Paul [167]

Answer:

0.08 mol L-1

Explanation:

Sulfuric acid Formula: H2SO4

Ammonia Formula: NH3

Ammonium sulfate Formula: (NH₄)₂SO₄

H2SO4 + 2NH3 = 2NH4+ + SO4 2-

H2SO4 + 2NH3 = (NH₄)₂SO₄

H2SO4 = (1/2)x (32.8 x 10^-3 L x 0.116 mol L-1)/25 x 10^-3 L

= 0.08 mol L-1

7 0

3 years ago

What is the energy released or absorbed as heat when one mole of a compound is produced by combination of its elements? select o

suter [353]

B and D is out. It cant be A because heat of combustion is substance not compound. So the answer is D.

7 0

3 years ago

Stoichiometry: Calculate the moles of H2 produced by .042 g Mg in the equation Mg + 2HCl > MgCl2 + H2

Evgesh-ka [11]

Answer:

Mg (s) + 2HCI2 (aq) → MgCI2 (aq) + H2 (g)

I think this is the correct answer I not a 100% sure if it is correct.

Explanation:

Guessing

6 0

3 years ago