1. Check the drawing of the rhombus ABCD in the picture attached.
2. m(CDA)=60°, and AC and BD be the diagonals and let their intersection point be O.
3. The diagonals:
i) bisect the angles so m(ODC)=60°/2=30°
ii) are perpendicular to each other, so m(DOC)=90°
4. In a right triangle, the length of the side opposite to the 30° angle is half of the hypothenuse, so OC=3 in.
5. By the pythagorean theorem,

6. The 4 triangles formed by the diagonal are congruent, so the area of the rhombus ABCD = 4 Area (triangle DOC)=4*

=

(

)
Answer:
24%
Step-by-step explanation:
45 + 37 + 52 + 94 + 72 = 300
72/300 = 0.24 x 100
= 24%
OK so my answer is from what you’ve just explained that means you multiply the six and the 114 is 684 so that means if you have to do that to 13 of them that means 684×13 is what your equation would be in the answer to 684×13 is 8892
40pie units squared / esa es
Answer:
Assuming that you are listing the length of each side of the figure, we can add the values together. The perimeter is 16 cm.
Step-by-step explanation:
6+2+2+6=16 cm