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Gnesinka [82]
4 years ago
15

A sin q B cot q C cos q D csc q

Mathematics
1 answer:
Natali [406]4 years ago
6 0
Answer: A



hope it helps
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When asked to write an equivalent expression to 5(a+3),Alejandra wrote 5a+8. Is she correct? If not, what is the correct answer?
Reika [66]

5a+8

Answer is NOT 5a+8

5(a+3) Multiply the bracket by 5

5(a)+5(3)

5a+15

Correct answer is supposed to be: 5a+15

4 0
4 years ago
A train accelerates at an average rate of 0.33 meter per second squared, and the
ANTONII [103]

Answer:

I don't know

Step-by-step explanation:

please mark me as the brainlist

3 0
3 years ago
(cosx/1-sinx)-secx=tanx
anastassius [24]

Answer:

The value of given trigonometrical expression is cos²x + sin²x = 1

Step-by-step explanation:

Given trigonometrical expression as :

( \dfrac{\textrm cos x}{\textrm 1-sin x} ) - sec x = tan x

Or, ( \dfrac{\textrm cos x}{\textrm 1-sin x} ) = tan x + sec x

or,  ( \dfrac{\textrm cos x}{\textrm 1-sin x} ) =  ( \dfrac{\textrm sin x}{\textrm cos x} )  +  ( \dfrac{\textrm 1}{\textrm cos x} )

or,  ( \dfrac{\textrm cos x}{\textrm 1-sin x} ) =  ( \dfrac{\textrm 1 + sin x}{\textrm cos x} )

Now, cross multiplying both side

I.e (cos x) ×  (cos x)  = ( 1 - sin x ) × ( 1 + sin x )

or, cos²x =  1 - sin² x  

or, cos²x + sin²x = 1

So, Value of expression is cos²x + sin²x = 1

Hence The value of given trigonometrical expression is cos²x + sin²x = 1 answer

7 0
3 years ago
Solve -28<2x-10<-10
Sedbober [7]
-28 < 2x - 10 < -10.....add 10 to all sections
-28 + 10 < 2x - 10 + 10 < -10 + 10....simplify
-18 < 2x < 0...divide all sections by 2
-18/2 < 2/2x < 0/2...simplify
-9 < x < 0 <===
5 0
3 years ago
A ladder leans against a brick wall. The foot of the ladder is 6 feet from the wall. The ladder reaches a height of 15 ft on the
Nady [450]

Answer:

The angle the ladder makes with the wall is equal to 22\°

Step-by-step explanation:

Let

x-------> the angle the ladder makes with the wall

see the attached figure to better understand the problem

we know that

In the right triangle ABC

tan(x)=\frac{AB}{BC}

we have

AB=6\ ft

BC=15\ ft

substitute

tan(x)=\frac{6}{15}

x=arctan(\frac{6}{15})=22\°

8 0
4 years ago
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