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3 years ago

A sample of size 39 will be drawn from a population with mean 23 and standard

Mathematics

1 answer:

Agata [3.3K]3 years ago

7 0

Answer:

it is b

Step-by-step explanation:

I did it on ed 2020

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The price of a holiday was decreased by 12% to £600. What was the price before

Naya [18.7K]

Answeidk i tried to read it but I dont getit

Step-by-step explanation:

5 0

3 years ago

What is the third quartile of this data set ? 14,18,20,21,25,32,40,44,48

kotykmax [81]

Step-by-step explanation:

Step 1 :

Given data set - 14,18,20,21,25,32,40,44,48

We need to get the 3rd quartile

Step 2 :

To find the quartile's , we have to divide the data set into 4 equal quarters.

The 3rd cut will give the 3rd quartile

Step 3:

The median of this data set is at 25, there are 4 numbers below and above it.

Now we take the 2nd half of the set , after the median and take the median of it.

There are 4 numbers in the 2nd half 32,40,44,48. Cutting this into 2 , we have the cut to fall between 40 and 44. Hence taking the average of this will give the 3rd quartile.

The average of 40 and 44 is 42 .

Hence the 3rd quartile is 42.

7 0

3 years ago

Work out (10-3 x 2) to the power of 2

Leno4ka [110]

Answer:

Step-by-step explanation:

parentheses first: 10-6 which is 4^2 or 16.

Hope this helps :D

8 0

3 years ago

Inequality help!<br><br>so I'm thinking it's choice one...would that be right?

professor190 [17]

The answer is choice 1

6 0

3 years ago

Find the fourth roots of 256(cos 240° + i sin 240°).

Mashcka [7]

Answer with Step-by-step explanation:

We are given that

We have to find the fourth roots of given complex number.

$(256)^{\frac{1}{4}}=(4^4)^{\frac{1}{4}}=4^^{\frac{1}{4}\times 4}=4$

By using the formula

$(a^b)^x=a^{bx}$

$\theta=240^{\circ}$

$\theta=\frac{240}{4}=60^{\circ}$

Angle of rotation= $\frac{360}{4}=90^{\circ}$

Therefore, the four roots of given complex number are

$4(cos 60^{\circ}+i sin60^{\circ})$

$4(cos150^{\circ}+i sin150^{\circ})$

$4(cos240^{\circ}+isin 240^{\circ})$

$4(cos330^{\circ}+i sin330^{\circ})$

8 0

3 years ago