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jenyasd209 [6]
3 years ago
11

The total number of electrons in one mole of fluorine molecules (F2) is

Chemistry
2 answers:
soldi70 [24.7K]3 years ago
6 0
<span>Fluorine's atomic number is 9, meaning it has 9 protons and 9 electrons in per atom. One mole is 6.0x10^23, so your answer is 4.</span>
galben [10]3 years ago
3 0
Has 9 protons and 9 electrons in per atom.........
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Non examples of chemical formulas
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True or false all countries are legally bound to survey and monitor for disease within their bodies
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7 0
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The increasing concentration of a chemical as it moves through the links in a food chain is called ________.
algol13

Answer: Biological Magnification

Explanation:

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4 0
3 years ago
Given the following balanced equation, if the rate of O2 loss is 3.64 × 10-3 M/s, what is the rate of formation of SO3? 2 SO2(g)
Fynjy0 [20]

Answer:

Rate of formation of SO₃ [\frac{d[SO_{3}] }{dt}] = 7.28 x 10⁻³ M/s

Explanation:

According to equation   2 SO₂(g) + O₂(g) → 2 SO₃(g)

Rate of disappearance of reactants = rate of appearance of products

                     ⇒ -\frac{1}{2} \frac{d[SO_{2} ]}{dt} = -\frac{d[O_{2} ]}{dt}=\frac{1}{2} \frac{d[SO_{3} ]}{dt}  -----------------------------(1)

    Given that the rate of disappearance of oxygen = -\frac{d[O_{2} ]}{dt} = 3.64 x 10⁻³ M/s

             So the rate of formation of SO₃ [\frac{d[SO_{3}] }{dt}] = ?

from equation (1) we can write

                                   \frac{d[SO_{3}] }{dt} = 2 [-\frac{d[O_{2}] }{dt} ]

                                ⇒ \frac{d[SO_{3}] }{dt} = 2 x 3.64 x 10⁻³ M/s

                                ⇒ [\frac{d[SO_{3}] }{dt}] = 7.28 x 10⁻³ M/s

∴ So the rate of formation of SO₃ [\frac{d[SO_{3}] }{dt}] = 7.28 x 10⁻³ M/s

7 0
3 years ago
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zheka24 [161]
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5 0
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