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Llana [10]
3 years ago
9

If you are using 3.00% (mass/mass) hydrogen peroxide solution and you determine that the mass of solution required to reach the

equivalence point is 5.125 g, how many moles of hydrogen peroxide molecules are present?
Chemistry
1 answer:
Maurinko [17]3 years ago
5 0

Answer:

0.004522 moles of hydrogen peroxide molecules are present.

Explanation:

Mass by mass percentage of hydrogen peroxide solution = w/w% = 3%

Mass of the solution , m= 5.125 g

Mass of the hydrogen peroxide = x

w/w\% = \frac{x}{m}\times 100

3\%=\frac{x}{5.125 g}\times 100

x=\frac{3\times 5.125 g}{100}=0.15375 g

Mass of hydregn pervade in the solution = 0.15375 g

Moles of hydregn pervade in the solution :

=\fraC{ 0.15375 g}{34 g/mol}=0.004522 mol

0.004522 moles of hydrogen peroxide molecules are present.

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Answer:

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Kaley has also developed a hypothesis and the experiment she conducted is also valid hence there is no problem in these steps.

There is no mistake being done by her in depicting the results of the experiment.

Hence, the only thing which we can say is missing from the experiment is the past researches which scientists might have made on this topic.

Explanation:

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4 years ago
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svetoff [14.1K]
When we have the balanced reaction equation is:

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7 0
4 years ago
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Oxana [17]

Answer:

A.  1.88 mol H₂

B.  182 g Al₂(SO₄)₃

C.  54.8%

Explanation:

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(100.0/182.48) × 100% = 54.8%

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Explanation:

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