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Llana [10]
3 years ago
9

If you are using 3.00% (mass/mass) hydrogen peroxide solution and you determine that the mass of solution required to reach the

equivalence point is 5.125 g, how many moles of hydrogen peroxide molecules are present?
Chemistry
1 answer:
Maurinko [17]3 years ago
5 0

Answer:

0.004522 moles of hydrogen peroxide molecules are present.

Explanation:

Mass by mass percentage of hydrogen peroxide solution = w/w% = 3%

Mass of the solution , m= 5.125 g

Mass of the hydrogen peroxide = x

w/w\% = \frac{x}{m}\times 100

3\%=\frac{x}{5.125 g}\times 100

x=\frac{3\times 5.125 g}{100}=0.15375 g

Mass of hydregn pervade in the solution = 0.15375 g

Moles of hydregn pervade in the solution :

=\fraC{ 0.15375 g}{34 g/mol}=0.004522 mol

0.004522 moles of hydrogen peroxide molecules are present.

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