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Llana [10]
2 years ago
9

If you are using 3.00% (mass/mass) hydrogen peroxide solution and you determine that the mass of solution required to reach the

equivalence point is 5.125 g, how many moles of hydrogen peroxide molecules are present?
Chemistry
1 answer:
Maurinko [17]2 years ago
5 0

Answer:

0.004522 moles of hydrogen peroxide molecules are present.

Explanation:

Mass by mass percentage of hydrogen peroxide solution = w/w% = 3%

Mass of the solution , m= 5.125 g

Mass of the hydrogen peroxide = x

w/w\% = \frac{x}{m}\times 100

3\%=\frac{x}{5.125 g}\times 100

x=\frac{3\times 5.125 g}{100}=0.15375 g

Mass of hydregn pervade in the solution = 0.15375 g

Moles of hydregn pervade in the solution :

=\fraC{ 0.15375 g}{34 g/mol}=0.004522 mol

0.004522 moles of hydrogen peroxide molecules are present.

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No amino acid molecule by itself can speed up or catalyze reactions between other molecules; however, when amino acids are joine
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Explanation:

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8 0
2 years ago
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According to the following reaction, how many grams of nitrogen monoxide will be formed upon the complete reaction of 31.0 grams
Mumz [18]

23.227 grams of NO is formed upon the complete reaction of 31.0 grams of oxygen gas with excess ammonia.

Explanation:

The balanced chemical equation is:

4NH3 + 5O2 ⇒ 4NO + 6H20

Number of moles will be calculated.

31 grams of oxygen is given

atomic weight of oxygen gas i.e O2 = 32gm/mole

The molar mass of oxygen gas is 32 grams/mole which is equal to one mole of the molecule.

Number of moles (n) = \frac{mass}{atomic mass of one mole of the substance}

                             n=    \frac{31}{32}

                              n = 0.968 moles of oxygen are given for the reaction to occur.

From the balanced chemical equation it can be seen

5 moles of oxygen yielded 4 moles of NO

So, 0.968 moles of oxygen yield x moles of NO

\frac{4}{5} = \frac{x}{0.968 }

4 × 0.968 =5x

x = 0.774 moles of NO will be formed.

To calculate the mass of NO

mass= atomic mass x number of moles

atomic mass of NO is 30.01 grams/mole

putting the values in the formula:

mass = 30.01 x 0.774

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3 years ago
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3 0
2 years ago
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How many moles of CCl4 are in 3.55L
marishachu [46]

Answer: 0.16 moles

Explanation: According to Avogadro's law, 1 mole of every gas at STP occupies a volume of 22.4 Liters.

Given: Volume occupied = 3.55 L

From Avogadro's law,

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3.55 L of CCl_4 correspond to=\frac{1}{22.4}\times 3.55=0.16moles

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3 years ago
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