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Vsevolod [243]
3 years ago
9

Please help me on this, I'm bring timed!!​

Mathematics
1 answer:
makkiz [27]3 years ago
6 0

Answer:

It's the second one

Hope that helps!

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Solve the simultaneous equation y-2x+1=0 and 4x^2+3y^2-2xy=7
Lapatulllka [165]

The first equation is y-2x+1=0

y=2x-1 (Equation 1)

The second equation is 4x^{2}+3y^{2}-2xy=7 (Equation 2)

Putting the value of x from equation 1 in equation 2.

we get,

4x^{2}+3(2x-1)^{2}-2x(2x-1)=7

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by simplifying the given equation,

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Using discriminant formula,

D=b^{2}-4ac

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Now the formula for solution 'x' of quadratic equation is given by:

x=\frac{-b+\sqrt{D}}{2a}  and  x=\frac{-b-\sqrt{D}}{2a}

x=\frac{5+\sqrt{73}}{12}  and x=\frac{5-\sqrt{73}}{12}

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A principal of $2900 is invested at 4.25% interest, compounded annually. How much will the investment be worth after 7 years?
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The S = So(1+i)t = $2,200(1.0325)13 = $3,334.21

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2 years ago
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