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2 years ago

The question goes like this:

Mathematics

2 answers:

gogolik [260]2 years ago

8 0

Answer:

You read 30 pages of the book.

You have 90 pages left.

Step-by-step explanation:

120 total pages

⇒ 120 = 100%

$\frac{1}{4}$ pages have been read

⇒ $\frac{1}{4}$ = 25%

$\frac{3}{4}$ remaining

⇒ $\frac{3}{4}$ = 75%

120 x .25 = 30 pages read

120 x .75 = 90 pages unread

30 + 90 = 120

Orlov [11]2 years ago

5 0

Answer:

You have 90 pages left.

Step-by-step explanation:

1/4 × 120 = 30 pages read

Therefore

120- 30

=90 pages left to read

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If the number of bacteria in a colony doubles every 25 hours and there is currently a population of 10,000 bacteria, what will t

MA_775_DIABLO [31]

Answer:

The population of 75 hours from now would be 40,000.

Step-by-step explanation:

The reason for this is because your initial number is 10,000 and when 25 hours pass by, your population would be 20,000. Another 25 hours pass by, and then your population would be 40,000. If you multiply 25 by 3, you will notice 75 hours have just passed, so your answer would be 40,000.

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3 years ago

If h(x) = x - 7 and g(x) = x^2 , which expression is equivalent to (gOh)(5)?

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(5 - 7)^2 is your answer

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3 years ago

4.06 Question 6

polet [3.4K]

Answer:

If we are to make x small rugs, each of which takes 2 hours to dye, then the total time taken to dye the small rugs is 2x. Similarly for the y large rugs which each take 3 hours to dye, the total time for dyeing the large rugs is 3y. Therefore the total for all sizes of rugs is 2x + 3y. Finally, we have a maximum of 60 available hours for the dyeing, so the total time cannot exceed 60, and the final inequality is

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Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

A recent study found that the average length of caterpillars was 2.8 centimeters with a

pogonyaev

Using the normal distribution, it is found that there is a 0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are given, respectively, by:

$\mu = 2.8, \sigma = 0.7$ .

The probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters is <u>one subtracted by the p-value of Z when X = 4</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4 - 2.8}{0.7}$

Z = 1.71

Z = 1.71 has a p-value of 0.9564.

1 - 0.9564 = 0.0436.

0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

More can be learned about the normal distribution at brainly.com/question/24663213

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1 year ago

In 1970, the average length of a major league baseball game was 150 minutes compared to 180 minutes in 2018. Calculate the absol

Pavlova-9 [17]

Answer:

30 min
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Step-by-step explanation:

The absolute change in game length is ...

(180 min) -(150 min) = 30 min . . . . change in game length

The relative change is expressed as a fraction of the original game length:

(30 min)/(150 min) × 100% = 20% . . . . relative change in game length

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2 years ago