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Tamiku [17]
3 years ago
11

4NH3 + 502 --> 4NO + 6H20

Chemistry
1 answer:
gregori [183]3 years ago
7 0

Answer:

5.52 g

Explanation:

  • 4NH₃ + 5O₂ → 4NO + 6H₂O

First we <u>convert the given masses of both reactants into moles</u>, using their <em>respective molar masses</em>:

  • 6.30 g NH₃ ÷ 17 g/mol = 0.370 mol NH₃
  • 1.80 g O₂ ÷ 32 g/mol = 0.056 mol O₂

Now we <u>calculate with how many NH₃ moles would 0.056 O₂ moles react</u>, using the<em> stoichiometric coefficients</em>:

  • 0.056 mol O₂ * \frac{4molNH_3}{5molO_2} = 0.045 mol NH₃

As there more NH₃ moles than required, NH₃ is the excess reactant.

Then we calculate how many NH₃ moles remained without reacting:

  • 0.370 mol NH₃ - 0.045 mol NH₃ = 0.325 mol NH₃

Finally we convert NH₃ moles into grams:

  • 0.325 mol NH₃ * 17 g/mol = 5.52 g
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Prokaryotic is the answer!

Explanation:

I know this because, the nucleolus is absent in the image.

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3 0
3 years ago
Explain why atoms would gain or lose electrons in order to resemble the elements in the particular group you named above. Consid
Leokris [45]

Answer:

The number of electrons in the outermost shell of an element is represented in the periodic table as the group number that element is situated in the number of electrons in all shells of an element is represented in the periodic table as the element's atomic number.

Explanation:

I hope that helps

4 0
3 years ago
How much heat is absorbed by a 2000 g granite rock as energy from the sun causes its temperature to change from 10°C to 29°C?
emmainna [20.7K]

Answer:

None of the options are correct. The correct answer is 30020J

Explanation:

Data obtained from the question include:

Mass (M) = 2000g

Initial temperature (T1) = 10°C

Final temperature (T2) = 29°C

Change in temperature (ΔT) = T2 - T1 = 29°C - 10°C = 19°C

Heat (Q) =?

Specific heat capacity (C) of granite = 0.79J/g°C

Applying the equation Q = MCΔT, the heat absorbed by the granite rock can be obtained as follow:

Q = MCΔT

Q = 2000 x 0.79 x 19

Q = 30020J

3 0
3 years ago
How many grams of water at 50◦c must be added to 16 grams of ice at −12◦c to result in only liquid water at 0◦c?
melisa1 [442]

When water at 50 C is added to ice at -12 C, heat is transferred from hot water to ice.

- Heat given out by water = Heat absorbed by ice

Calculating the heat released by hot water:

q = m CwaterΔTq = m (4.184\frac{J}{(g.^{0}C)} )(0^{0}C-50^{0}C)

Calculating heat absorbed by 16 g of ice: Ice at -12^{0}C is converted to ice at O^{0}C and then ice at O^{0} C to water at 0^{0}C

q = m CiceΔT + m (Heat of fusion)

q = 16 g(2.11\frac{J}{g.^{0}C})(0^{0}C - (-12^{0}C)) + 16 g (333.55\frac{J}{g})

q = 405.12 J +5336.8 J =5741.92 J

- Heat given out by water = Heat absorbed by ice

-(m(4.184\frac{J}{g.^{0}C})(0^{0}C-50^{0}C) = 5741.92 J

m = 27.4 g

Therefore, 27.4 g water at 50^{0}C must be added to 16 g of ice at -12^{0}C to convert to liquid water at 0^{0}C

4 0
3 years ago
When a substance undergoes a Chemical Change, can the change be reversed? Explain your answer.​
Vinvika [58]

Answer:When a substance undergoes a chemical change some of the chemical changes can be reversed with a chemical change.

Explanation:

A chemical change changes all of the element but some chemical changes but very few can be changed back to its original substance only with a chemical change.

3 0
3 years ago
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