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____ [38]
3 years ago
12

Explain why metals can conduct electricity and heat well

Chemistry
1 answer:
bekas [8.4K]3 years ago
8 0
Electric current is the flow of electrons in a wire. In metals, the outer electrons of the atoms belong to a 'cloud' of delocalised electrons. They are no longer firmly held by a specific atom, but instead they can move freely through the lattice of positive metal ions. ... Metals are good conductors of heat.
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Which two solutions, when mixed together, will undergo a double replacement reaction and form a white, solid substance?
IceJOKER [234]

AgNO_3 + KCl → AgCl + KNO_3 undergo a double replacement reaction and form a white, solid substance. Hence, option B is correct.

<h3>What is a double replacement reaction?</h3>

A double replacement reaction is a type of chemical reaction that occurs when two reactants exchange cations or anions to yield two new products.

Double-replacement reactions generally occur between substances in aqueous solution. In order for a reaction to occur, one of the products is usually a solid precipitate, a gas, or a molecular compound such as water.

AgNO_3 + KCl → AgCl + KNO_3 undergo a double replacement reaction and form a white, solid substance.

Hence, option B is correct.

Learn more about the double replacement reaction here:

brainly.com/question/19267538

#SPJ1

4 0
2 years ago
What type of compound does the formula, CO2, represent?<br> a. ionic salt<br> b. covalent molecule
vekshin1
B since both elements are nonmetals
7 0
3 years ago
Read 2 more answers
If you were asked to convert 3.5 moles of aluminum to grams, which of the following should you use for the conversion? . Select
Zolol [24]
To convert the given number of moles of aluminum to grams, we need to use the molar mass of the element as the conversion factor. Aluminum has a molar mass of 26.981 g/ mol. The answer to this problem is b. <span>fraction: 26.981 g Al over one mol Al. </span>
6 0
3 years ago
The variable that we change or test in an experiment is called the
Anastaziya [24]

the variable that we change in an experiment is the Independent Variable. The dependent variable is the outcome and the constant is what remains the same throughout the experiment.

4 0
3 years ago
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Al2(SO4)3(s) + H2O(l) ---- Al2O3(s) + H2SO4 (aq) calculate enthalpy formation for this reaction. Balance the reaction. Calculate
katen-ka-za [31]

The given chemical equation is:

Al_{2}(SO_{4})_{3}(aq)+H_{2}O(l)-->Al_{2}O_{3}(aq)+H_{2}SO_{4}(aq)

On balancing the equation we get,

Al_{2}(SO_{4})_{3}(aq)+3H_{2}O(l)-->Al_{2}O_{3}(aq)+3H_{2}SO_{4}(aq)

Calculating enthalpy of formation of this reaction from the standard heats of formation of the products and reactants:

ΔH_{reaction}^{0}=[H_{f}^{0}(Al_{2}O_{3}(s)) + (3*H_{f}^{0}(H_{2}SO_{4}(aq))] -   [H_{f}^{0}(Al_{2}SO_{4}(aq)) + (3*H_{f}^{0}(H_{2}O(l))]

=[(-1669.8kJ/mol)+ {3* (-909.27 kJ/mol)}]-[(-3442kJ/mol)+{3*(-285.8 kJ/mol)}]

=[(-4397.61kJ/mol)]-[(-4299.4kJ/mol)]

=-98.21kJ/mol

Total enthalpy change when 15 mol of Al_{2}(SO_{4})_{3}reacts will be=

15 mol Al_{2}(SO_{4})_{3}*\frac{-98.21kJ}{1 molAl_{2}(SO_{4})_{3}} =-1473.15kJ/mol

4 0
4 years ago
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