Did you mean "atp"? if so It is less I hope this helps please mark brainliest :)
Answer:
1.17 grams of HCl can neutralize 2.7 grams sodium bicarbonate
Explanation:
Step 1: Data given
Mass of sodium bicarbonate = 2.7 grams
Step 2: The balanced equation
HCl + NaHCO3 ⇔ NaCl + H2O + CO2
Step 3: Calculate moles NaHCO3
moles NaHCO3 =2.7 g / 84 g/mol= 0.032 moles
Step 4: Calculate moles HCl
For 1 mol NaHCO3 we need 1 mol HCl
For 0.032 moles NaHCO3 = 0.032 moles HCl
Step 5: Calculate mass HCl
Mass HCl = moles HCl * molar mass HCl
mass HCl = 0.032 * 36.46 g/mol= 1.17 grams
1.17 grams of HCl can neutralize 2.7 grams sodium bicarbonate
Answer:
- <u><em>294.307 g/mol</em></u>
Explanation:
The first question for this statment is:
- <em>Calculate the gram-formula-mass of aspartame. </em>
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<h2>Solution</h2>
The chemical formula is:

The <em>gram-formula-mass </em>is calculated adding the masses for all the atoms in the molecular formula:
Atom Number of atoms Atomic mass Total mass
g/mol g/mol
C 14 12.011 14 × 12.011 = 164.154
H 18 1.008 18 × 1.008 = 18.144
N 2 14.007 2 × 14.007 = 28.014
O 5 15.999 5 × 15.999 = 79.995
===================
Total 294.307 g/mol
Answer: 294.307 g/mol
The first one is some reaction with water even I am studying the same
It will be the second one