So if it is 2.35L at the temperature 20.0^C and you want the volume at -5.00^C this is hw you would solve it for example 20.0^C to 2.00L it would be 10 degrees per Liter so it would be here 10 degrees every liter so you would do 20.0 % 2.35 = / then find the answer and then find out how many degrees that answer is off of -5.00 then once you get that divide -5.00 with that answer.<span>
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When you transferred the hot metal from the boiling water and into the calorimeter, The effect will be
- Change in temp is positive
- Temp of metal V, dT=-ve
- No change occurs in the specific heat of metal
This is further explained below.
<h3>What is the Specific heat of the metal?</h3>
a )Since the metal of the cup is hot and the water inside is cold, the water's temperature will rise as heat is transferred from the metal to the liquid.
Change in temp is positive
b)
Due to (a), heat is lost from the food to the water in the cup, lowering the metal's temperature.
Temp of metal V, dT=-ve
c)
No change occurs in the specific heat of metal because of its constant property.
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D, because C12 means there's 12 atoms of carbon.
Answer:
[H+] = 1.74 x 10⁻⁵
Explanation:
By definition pH = -log [H+]
Therefore, given the pH, all we have to do is solve algebraically for [H+] :
[H+] = antilog ( -pH ) = 10^-4.76 = 1.74 x 10⁻⁵
pH. 10 because it is strong base
