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3 years ago

A(n) 19000 kg freight car is rolling along a track at 1.5 m/s. Calculate the time needed for a force of 2600 N to stop the car.

Physics

1 answer:

garik1379 [7]3 years ago

7 0

Answer: 10.96secs

Explanation:

According to newton's second law

Force = mass × acceleration

F = ma

F = m(v-u)/t

Cross multiplying we have

Ft = m(v-u)

t = m(v-u)/F

Given F = 2600N m = 19,000kg v = 1.5m/s u = 0m/s

Substituting this values in the formula for the time we have

t = 19000(1.5-0)/2600

t = 28,500/2600

t= 10.96secs

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Answer:

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Answer:

Magnitude = 3.64 × $10^6$

စ = 43.9°

Explanation:

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