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Law Incorporation [45]
2 years ago
8

3(12x – 9) + 9 = 2x + 4 Would this be infinite solution, one solution or no solution?

Mathematics
1 answer:
timama [110]2 years ago
8 0

Answer:

One solution

Step-by-step explanation:

Let us first <u>expand</u> the left side of the equation to rid of the parenthesis:

3*12x-3*9+9=2x+4\\36x-27+9=2x+4\\36x-18=2x+4

Now let us <u>isolate</u> the variable to sove for x:

36x-2x=4+18\\34x=22\\x=\frac{22}{34}\\x=\frac{11}{17}

Therefore, x=\frac{11}{17}. As you can see, there is just one solution.

<em>I hope this helps! Please let me know if you have any further questions :)</em>

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I am so confused. Can anyone help me??
natita [175]

Answer:

bro!  im in 7th grade i would try to help but im very stupid sorry for the dissopiontment

Step-by-step explanation:

8 0
3 years ago
AYOOO PLZ HELP ASAP!!!
tamaranim1 [39]

Answer:

B.

Step-by-step explanation:

Well we know that

224=2^{5} *7

so we can get the 2 outside of the radical

x^{11} =(x^{5} )^{2} *x

and we can get the x^2 outside too.

y^8=y^5*y^3

and we also can get y outside.

so we have:

2x^{2}y\sqrt[5]{7xy^3}

7 0
2 years ago
On his drive from Montpelier, Vermont, to Columbia, South Carolina, Arthur averaged 51 mph. If he had been able to average 60 mp
Llana [10]

Answer:

Distance between Montpelier and Columbia is 1020

Step-by-step explanation:

51 mi/hr average:

d = 51 t  

60 mi/hr average:

d t = 60*(t-3)

Substitute (1) into (2)  

   51 t =  60*(t-3)

   51 t =  60 t + 180

   9 t  =  180

   t    =   20

d = 51 t

   = 51 (20)

   = 1020

let see distance is 1020 lets check

51 t = 60 * (t-3)

51 (20)= 60* (20-3)

1020   = 60*17

1020 = 1020

4 0
3 years ago
Use the standard norml distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justif
dalvyx [7]

Answer:

E) we will use t- distribution because is un-known,n<30

the confidence interval is (0.0338,0.0392)

Step-by-step explanation:

<u>Step:-1</u>

Given sample size is n = 23<30 mortgage institutions

The mean interest rate 'x' = 0.0365

The standard deviation 'S' = 0.0046

the degree of freedom = n-1 = 23-1=22

99% of confidence intervals t_{0.01} =2.82  (from tabulated value).

The mean value = 0.0365

x±t_{0.01} \frac{S}{\sqrt{n-1} }

0.0365±2.82 \frac{0.0046}{\sqrt{23-1} }

0.0365±2.82 \frac{0.0046}{\sqrt{22} }

0.0365±2.82 \frac{0.0046}{4.690 }

using calculator

0.0365±0.00276

Confidence interval is

(0.0365-0.00276,0.0365+0.00276)

(0.0338,0.0392)

the mean value is lies between in this confidence interval

(0.0338,0.0392).

<u>Answer:-</u>

<u>using t- distribution because is unknown,n<30,and the interest rates are not normally distributed.</u>

4 0
3 years ago
Please give me the right answer I need help
Nimfa-mama [501]
Area of fountain is 147.58 and area of path is 28.26
4 0
3 years ago
Read 2 more answers
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