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3 years ago

Please help will name brainliest

Mathematics

2 answers:

Vera_Pavlovna [14]3 years ago

7 0

C I am sorry if I am wrong

Bess [88]3 years ago

6 0

The answer is the one that is perhaps correct yeah

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(6,3); (1,4)<br><br> Slope<br><br> Giving brainless answer

dezoksy [38]

(6,3) (1,4)
4-1/3-6
3/-3
The slope is -1
Hope that helped

7 0

2 years ago

Read 2 more answers

WILL MARK BRAINLIEST!!! PLEASE ANSWER!!! WRONG ANSWERS JUST FOR POINTS WILL BE REPORTED!!!!!!!!!!!!!!

alexgriva [62]

Answer:

916.1 cm^3

Step-by-step explanation:

1) find the radius of the cylinder:

radius = dimater / 2 = 7,3 / 2 = 3.65 cm

2) find the base area of the cylinder:

base area = radius^2 x 3.14 = 3.65^2 x 3.14 = 41.83265 cm^2

3) find the height of the cylinder:

height = 7.3 x 3 = 21.9 cm

4) find the volume

V = base area x height = 41.83265 x 21.9 = 916.135035 cm^3

5) round to nearest tenth:

916. 1 cm^3

5 0

3 years ago

The parking lot at a store has a width of 20 yards 2 feet and a length of 30 yards

Liula [17]

Answer:

I guess you are trying to find the perimeter of the parking lot.

the fomula is P= 2L+2W.

Step by step:

20yards( 2 ft )+ 30 yards +20 yards + 30 yards=

100 yards 2 ft.

I hope it's help.

5 0

3 years ago

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Find the inverse of the given matrix, if it exists.Aequals=left bracket Start 3 By 3 Matrix 1st Row 1st Column 1 2nd Column 0 3

BabaBlast [244]

Answer:

$A^{-1}=\left[ \begin{array}{ccc} \frac{1}{9} & \frac{4}{27} & - \frac{2}{27} \\\\ \frac{8}{9} & \frac{5}{27} & \frac{11}{27} \\\\ - \frac{4}{9} & \frac{2}{27} & - \frac{1}{27} \end{array} \right]$

Step-by-step explanation:

We want to find the inverse of $A=\left[ \begin{array}{ccc} 1 & 0 & -2 \\\\ 4 & 1 & 3 \\\\ -4 & 2 & 3 \end{array} \right]$

To find the inverse matrix, augment it with the identity matrix and perform row operations trying to make the identity matrix to the left. Then to the right will be inverse matrix.

So, augment the matrix with identity matrix:

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 4&1&3&0&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]$

Subtract row 1 multiplied by 4 from row 2

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]$

Add row 1 multiplied by 4 to row 3

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&2&-5&4&0&1\end{array}\right]$

Subtract row 2 multiplied by 2 from row 3

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&-27&12&-2&1\end{array}\right]$

Divide row 3 by −27

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

Add row 3 multiplied by 2 to row 1

$\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

Subtract row 3 multiplied by 11 from row 2

$\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&0&\frac{8}{9}&\frac{5}{27}&\frac{11}{27} \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

As can be seen, we have obtained the identity matrix to the left. So, we are done.

6 0

3 years ago

Solve eqaution 15m+22=-7m+18

lilavasa [31]

It will beee 22/4 :)....

7 0

3 years ago

Read 2 more answers