Answer:
20.53 g.
Explanation:
- Knowing that every 15.0 g of pure calcium fluoride contains 7.70 g of calcium.
<u>Using cross multiplication:</u>
15.0 g of pure calcium fluoride contains → 7.70 g of calcium.
40.0 g of pure calcium fluoride contains → ??? g of calcium.
<em>∴ The mass of Ca in 40.0 g of calcium fluoride</em> = (7.70 g)(40.0 g)/(15.0 g) = <em>20.53 g.</em>
It is B: Fixed volume, takes the shape of the container
<span>Fe + O2 ----> Fe2O3
</span>4Fe + 3O2 ----> 2Fe2O3
Left Hand Side;
Fe=4
O2=6
Right Hand Side:
Fe=4
O2=6