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anastassius [24]
3 years ago
12

Consider the following system at equilibrium: P(aq)+Q(aq)⇌3R(aq) Classify each of the following actions by whether it causes a l

eftward shift, a rightward shift, or no shift in the direction of the net reaction. Drag the appropriate items to their respective bins.
Items:1) Increase [P]2) Increase [Q]3) Increase [R]4) Decrease [P]5) Decrease [Q]6) Decrease [R]7) Triple [P] and reduce [Q] to one third8) Triple both [Q] and [R]
Chemistry
1 answer:
Dahasolnce [82]3 years ago
3 0

Explanation:

P(aq)+Q(aq)⇌3R(aq)

This problem involves applying LeChatelier's principle.

LeChatelier's principle states that whenever a system in equilibrium is disturbed, the equilibrium position would change in order to annul that change.

1) Increase [P]

This would cause the equilibrium position to shift to the right. This is because more reactions have been added, to annul that change more products have to be formed.

2) Increase [Q]

This would cause the equilibrium position to shift to the right. This is because more reactions have been added, to annul that change more products have to be formed.

3) Increase [R]

This would cause the equlibrium position to shift to the left. This is because more products have been formed, to annul that change more reactants have to be formed.

4) Decrease [P]

This would cause the equlibrium position to shift to the left. This is because there are now less reactants, to annul that change more reactants have to be formed.

5) Decrease [Q]

This would cause the equilibrium position to shift to the left. This is because there are now less reactants, to annul that change more reactants have to be formed.

6) Decrease [R]

This would cause the equilibrium position to shift to the right. This is because there are now less products, to annul that change more products have to be formed.

7) Triple [P] and reduce [Q] to one third

No shift in the direction of the net reaction because both changes cancels each other.

8) Triple both [Q] and [R]

No shift in the direction of the net reaction because both changes cancels each other.

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Most Bic lighters hold 5.0ml of liquified butane (density = 0.60 g/ml). Calculate the minimum size container you would need to "
Hatshy [7]

Answer:

Volume of container = 0.0012 m³ or 1.2 L or 1200 ml

Explanation:

Volume of butane = 5.0 ml

density = 0.60 g/ml

Room temperature (T) = 293.15 K

Normal pressure (P) = 1 atm = 101,325 pa

Ideal gas constant (R) = 8.3145 J/mole.K)

volume of container V = ?

Solution

To find out the volume of container we use ideal gas equation

PV = nRT

P = pressure

V = volume

n = number of moles

R = gas constant

T = temperature

First we find out number of moles

<em>As Mass = density × volume</em>

mass of butane = 0.60 g/ml ×5.0 ml

mass of butane = 3 g

now find out number of moles (n)

n = mass / molar mass

n = 3 g / 58.12 g/mol

n = 0.05 mol

Now put all values in ideal gas equation

<em>PV = nRt</em>

<em>V = nRT/P</em>

V = (0.05 mol × 8.3145 J/mol.K × 293.15 K) ÷ 101,325 pa

V = 121.87 ÷ 101,325 pa

V = 0.0012 m³ OR 1.2 L OR 1200 ml

8 0
4 years ago
Determine whether the statement is true or false, and why. "If a theory becomes supported by evidence, it can become a law."
loris [4]

Answer: D. False, it should read, "A theory and a law are already both supported by evidence and are equal, but they have different functions."

Explanation:

A  "Theory" and  a'' Law" in scientific method are already both supported by evidence but they have different function,

The function of  " Theory" in scientific method is to give an explanation to the observations and findings gathered during the process. It can be modified, improved or even rejected as more information is being gathered.

While a '' Law '' tends to describe an observed event in nature that is true whenever it is put to test. It does not explain why the occurence or event is true.

5 0
3 years ago
How many moles would be equal to 22.4 g of CO2?
Rzqust [24]

Answer:

Number of moles = 0.51 mol

Explanation:

Given data:

Mass of CO₂ = 22.4 g

Number of moles = ?

Solution:

Number of moles of CO₂:

Number of moles = mass/molar mass

Molar mass of CO₂ = 44 g/mol

by putting values,

Number of moles = 22.4 g/ 44 g/mol

Number of moles = 0.51 mol

4 0
3 years ago
Determine the number of moles of N atoms in 46.5g of Mg(NO3)2
Flura [38]
First, we determine the moles of Mg(NO₃)₂ present:
moles = mass / Mr
= 46.5 / (24 + 2 x (14 + 16 x 3))
= 0.4 mole

Each mole of Mg(NO₃)₂ contains 2 moles of Nitrogen atoms.
Moles Nitrogen = 0.4 x 2
= 0.8 mole
4 0
3 years ago
Passing an electric current through a sample of water (H2O) can cause the water to decompose into hydrogen gas (H2) and oxygen g
Tema [17]

<u>Answer:</u> The mass of water that must be reacted is 56.28 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      ....(1)

Given mass of oxygen = 50 g

Molar mass of oxygen = 32.00 g/mol

Putting values in equation 1, we get:

\text{Moles of oxygen}=\frac{50g}{32g/mol}=1.5625mol

For the given chemical equation:

2H_2O\rightarrow 2H_2+O_2

By Stoichiometry of the reaction:

1 mole of oxygen is produced when 2 moles of water is reacted.

So, 1.5625 moles of oxygen is produced when = \frac{2}{1}\times 1.5625=3.125mol of water is reacted.

To calculate the mass of water, we use equation 1:

Moles of water = 3.125 moles

Molar mass of water = 18.01 g/mol

Putting values in equation 1, we get:

3.125mol=\frac{\text{Mass of water}}{18.01g/mol}\\\\\text{Mass of water}=56.28g

Hence, the mass of water that must be reacted is 56.28 grams.

3 0
4 years ago
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