Question

If a 50 N force pulls on a 10 kg object,how much acceleration will occur?

Answer 1

Answer:

The value of acceleration occurred is $5 m/s^2$.

Explanation:

Force is a push or pull on an object with mass which causes in change in its velocity Or it  is the product of its mass and acceleration by which that object is moving.

Force =$mass\times acceleration$

F = ma

We have:

F = 50 N, a = ? , m = 10 kg

Putting in the values we get,

$50 N=10 kg\times a$

$a=\frac{50 N}{10 kg}=5 m/s^2$

The value of acceleration occurred is $5 m/s^2$.

Answer 2

Assuming that the force of friction does not equal to the force at which you are pulling at, hence Fnet is not zero, to solve for acceleration need to use the following equation:

Fnet = ma
a = Fnet/m
a = 50 N/10 kg
a = 5 N/kg or a = 5 m/s^2.