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klemol [59]
3 years ago
13

PLEASE HELP

Mathematics
2 answers:
avanturin [10]3 years ago
7 0

Answer:

a) 11/7 pages or about 1.57

b) 23/11 dollars or 2.09090909....... (goes on forever)

Step-by-step explanation: hope this helps

jolli1 [7]3 years ago
5 0

Answer:

a) 11/7 pages or about 1.57

b) 23/11 dollars or 2.09090909....... (goes on forever)

BRAINLIEST PLS

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Work out and simplify where possible<br><br>7/15+2/15​
alisha [4.7K]

Answer:

3/5

Step-by-step explanation:

7/15 + 2/15 = 9/15

both 9 nad 15 are divisible by 3

9/15 = 3/5

6 0
3 years ago
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There is a population of 139 bacteria in a colony. If the number of bacteria doubles every 189
Levart [38]

Answer:

556

Step-by-step explanation:

So, 378/189=2. So it will double two times. x2x2=x4. 139x4=556.

4 0
2 years ago
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F(x) = 3x2 - 7 and g(x) = x3 + 1, evaluate f(g(2)). NEED HELP PLEASEE??
Triss [41]
F(g(2)) = 3(x^3 + 1)^2 - 7 = 3(x^6 + 2x^3 + 1) - 7 = 3x^6 + 6x^3 + 3 - 7 = 3x^6 + 6x^3 - 4
7 0
3 years ago
P(k)=a^k=2 3 4 find value of a that makes this is a valid probability distribution
Vesna [10]
Sounds like you're asked to find a such that

\displaystyle\sum_{k=2}^4\mathbb P(k)=\mathbb P(2)+\mathbb P(3)+\mathbb P(4)=1

In other words, find a that satisfies

a^2+a^3+a^4=1

We can factorize this as

a^4+a^3+a^2-1=a^3(a+1)+(a-1)(a+1)=(a+1)(a^3+a-1)=0

In order that \mathbb P(k) describes a probability distribution, require that \mathbb P(k)\ge0 for all k, which means we can ignore the possibility of a=-1.

Let a=y+\dfrac xy.

a^3+a-1=\left(y+\dfrac xy\right)^3+\left(y+\dfrac xy\right)-1=0
\left(y^3+3xy+\dfrac{3x^2}y+\dfrac{x^3}{y^3}\right)+\left(y+\dfrac xy\right)-1=0

Multiply both sides by y^3.

y^6+3xy^4+3x^2y^2+x^3+y^4+xy^2-y^3=0

We want to find x\neq0 that removes the quartic and quadratic terms from the equation, i.e.

\begin{cases}3x+1=0\\3x^2+x=0\end{cases}\implies x=-\dfrac13

so the cubic above transforms to

y^6-y^3-\dfrac1{27}=0

Substitute y^3=z and we get

z^2-z-\dfrac1{27}=0\implies z=\dfrac{9+\sqrt{93}}{18}
\implies y=\sqrt[3]{\dfrac{9+\sqrt{93}}{18}}
\implies a=\sqrt[3]{\dfrac{9+\sqrt{93}}{18}}-\dfrac13\sqrt[3]{\dfrac{18}{9+\sqrt{93}}}
6 0
4 years ago
What is the inequality shown?<br> -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1<br> 2 3 4 5 6 7 8 9
ludmilkaskok [199]

Answer:

+1

Step-by-step explanation:

Well (+) and (-) is equals basically to (-) when add ing them or multiplying them... so the difference is +1

4 0
3 years ago
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