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nataly862011 [7]
3 years ago
14

Determine the number of solutions 3x + 1 = 4x - 2

Mathematics
1 answer:
TEA [102]3 years ago
3 0

Answer:

one solution

Step-by-step explanation:

1. 1=4x-2-3x

2. 1=x-2

3. 1+2=x

4. 3=x

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Solve the system of equations by substitution 3x+y=9z
poizon [28]

Answer:

x = 1.27

y = 5.18

Step-by-step explanation:

to solve this system of  equation by simultaneous equation we say that let

3x+y=9.............................. equation 1

-5x+2y=4 .......................... equation 2

from equation 1

3x+y=9.............................. equation 1

y = 9 -3x.............................. equation 3

substitute the value of y = 9 -3x into equation 2

-5x+2y=4 .......................... equation 2

-5x + 2( 9 -3x) = 4

-5x + 18 - 6x = 4

collect the like terms

18 - 4 = 6x + 5x

14 = 11x

divide both side by 11

14/11 = 11x/11

x = 14/11

x = 1.27

put the value of x = 1.27 into  equation 3

y = 9 -3x.............................. equation 3

y = 9 - 3( 1.27)

y = 9 - 3.82

y = 5.18

<em>to check if you are correct put the value of x and y into either equation 1 or equation 2.</em>

<em>3x+y=9.............................. equation 1</em>

<em>3( 1.27) + 5.18 = 9</em>

<em>3.81 + 5.18 = 9</em>

<em>9 = 9</em>

3 0
3 years ago
Which solutions is the correct one?
Debora [2.8K]

Answer:

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5 0
3 years ago
Read 2 more answers
The formula s= sqrt SA/6
ikadub [295]
For this case we have the following equation:
 s = root (S.A / 6)
 Substituting values we have:
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 s = root (180/6)
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 For S.A = 120:
 s = root (120/6)
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 root (30) - 2 * root (5)
 Answer:
 
root (30) - 2 * root (5)
 
option 2
3 0
3 years ago
F(x)=3x^3-4x^2+6x and g(x)=5x^3+2x^2-3x<br>what is f(X) AND G (X)
kvasek [131]
This on is very easy go to my website so i can explain it better for you

 <span>https://www.youtube.com/channel/UCaxhPMTZBmFcxAZ4hYpBf_w 
</span>
Hope this 
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3 years ago
A line passes through the points (2,4) and (5,6) . Select Yes or No to tell whether each equation describes this line. Equation
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\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-4}{5-2}\implies \cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-4=\cfrac{2}{3}(x-2)

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3 years ago
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