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goldfiish [28.3K]
3 years ago
7

"how is the stomach lining protected from the strongly acidic ph of its contents?"

Chemistry
1 answer:
SIZIF [17.4K]3 years ago
6 0
It is protected by a mucus layer formed on the surface regularly that ressist ph values.If it isn't formed our body will eat itself.
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The change in momentum experienced by a object is equivalent to the...
ivanzaharov [21]

Answer is: c. impulse acting on the object.

Momentum is the product of the mass and velocity of an object. It is a vector quantity, possessing a magnitude and a direction in three-dimensional space.

The impulse-momentum change equation: F· t = m · Δ v.

The impulse experienced by the object equals the change in momentum of the object.

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3 years ago
Heart, 5 stars, and Brainiest to first right answer!
erastovalidia [21]

hi have a nice day

will be less than 26 °C as water has a relatively higher specific heat than sand.

Explanation:

The specific heat of a substance is the amount of heat energy absorbed by one unit of mass of the substance when its temperature increases one unit.

From that, you can derive the equation for the specific heat of a substance:

specific heat = heat / (mass × ΔT)

Thus, assuming that all the heat provided by the lamp to both samples is the same and, as given, the amount (mass) of both samples is also the same, you have that the specific heat of the samples will be:

specific heat = constant / ΔT

So, specific heat and ΔT are inversely related.

It is known that water has a higher specific heat than sand (that is why the sand on the shore of a beach is, during the day, hotter than the water and your feet get burned when you walk on a sandy beach on a sunny day

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2 years ago
A 0.875-g sample of anthracite coal was burned in a bomb calorimeter. The temperature rose from 22.50 to 23.80°C. The heat capac
kherson [118]

Answer:

a) 26.65 kJ was the heat evolved by the reaction.

b) 3.046\times 10^7 kJ is the energy released on burning 1 metric ton  of this type of coal

Explanation:

Heat capacity of the calorimeter = C = 20.5 kJ/°C

Initial temperature of the calorimeter,T_1 = 22.50°C

Final temperature of the calorimeter,T_2 = 23.80°C

The heat evolved by the reaction = Q

Q=C(T_2-T_1)

Q=20.5 kJ/^oC\times (23.80^oC-22.50^oC)

Q=26.65 kJ

26.65 kJ was the heat evolved by the reaction.

0.875 g sample of anthracite coal was burned in a bomb calorimeter

0.875 g sample of anthracite coal gives 26.65 kJ of heat.

1 metric ton= 1000 kg

1000 kg = 1000 × 1000 g = 1,000,000 (1 kg =1000 g)

Then burning 1,000,000 g coal will give:

=\frac{26.65 kJ }{0.875}\times 1,000,000 g=3.046\times 10^7 kJ

3.046\times 10^7 kJ is the energy released on burning 1 metric ton  of this type of coal

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