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Alex Ar [27]
3 years ago
15

A charge of 1.7 C causes a force of 1.5 N. What is the magnitude of the electric field?

Physics
1 answer:
siniylev [52]3 years ago
5 0

<u>Answer</u>:

0.88 N / C

<u>Explanation</u>:

Given :

Charge ( q ) = 1.7 C

Force ( F ) = 1.5 N

We have to find electric field ( E ):

We know:

E = F / q

= > E = 1.5 / 1.7 N / C

= > 0.88 N / C

Hence we get required answer!

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The pressure at the bottom of a full barrel of water is Poriginal . Determine what happens to the pressure when the radius or he
Sholpan [36]

Answer:

a)   P' = P_original, b)  P ’= P_original + ρ  g Δh

Explanation:

The expression for nanometric pressure is

          P = ρ g h

where ρ  is the density of the liquid and h is the height

a) we change the radius of the barrel, but keeping the same height

as the pressure does not depend on the radius it remains the same

        P' = P_original

b) We change the barrel height

         h ’≠ h

we substitute in the equation

      P ’= ρ  g h’

      h ’= h + Δh

      P ’= ρ  g (h + Δh)

      P ’= (ρ  g h) + ρ  g Δh

      P ’= P_original + ΔP

In this case, the pressure changes due to the new height,

*if it is higher than the initial one, the pressure increases

*if the height is less than the initial one, the pressure is less

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3 years ago
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Three 40w lamp for 6 hours
8 0
4 years ago
To construct an oscillating LC system, you can choose from a 11 mH inductor, a 6.0 μF capacitor, and a 4.2 μF capacitor. What ar
Free_Kalibri [48]

Answer:

a. 475.14 Hz

b. 1959 Hz

c. 2341.53 Hz , 3053.34 Hz

Explanation:

f = \frac{1}{2\pi*\sqrt{C*L}}

a. smallest use the capacitive 4.2 uF + 6.0 uF = 10.2uF  replacing:

f = \frac{1}{2\pi*\sqrt{C*L}}f=\frac{1}{2\pi*\sqrt{10.2uF*11mH}}

f = 475.14 Hz

b. second smallest use the capacitive 6 uF so:

f = \frac{1}{2\pi*\sqrt{C*L}}=f = \frac{1}{2\pi*\sqrt{6uF*11mH}}

f = 1959Hz

c. second largest and largest oscillation first combination so:

Use 4.2 uF

f = \frac{1}{2\pi*\sqrt{C*L}}=f = \frac{1}{2\pi*\sqrt{4.2uF*11mH}}

f = 2341.53 Hz

And finally largest oscillation cap in serie so:

C=\frac{c_1*c_2}{c_1+c_2}=\frac{4.2uF*6.0uf}{4.2uf+6.0uF}

C=2.47 uF

f = \frac{1}{2\pi*\sqrt{C*L}}=f = \frac{1}{2\pi*\sqrt{2.47uF*11mH}}

f =  3053.34 Hz

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What is the relationship between the speed of impact and the dropping height?
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The difference is that speed means how fast u go and height is how tall you are..
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Answer: What Question

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