Hello from MrBillDoesMath!
Answer:
5
Discussion:
Consider the expansion of e^x:
e^x = 1 + x + x^2/2 + x^3/6 +...... => replace x by 5t
e^(5t) = 1 + (5t) + (5t)^2/2 + .... => subtract 1 from both sides
e^(5t) - 1 = (5t) + (5t)^2/2+.... => divide both sides by t
(e^(5t) -1)/ t = 5 + (25/2) t +....
so as t ends to 0 the quotient tends to
5 + (25/2)0 + (other terms) *0 -> 5
Thank you,
MrB
Answer:
3. x
-1
5. n
6
7. n
11
Step-by-step explanation:
3. -7+x-8 5. n-24 7. -18+n
-7
+7 +7 +2 +2 +18 +18
x-1 n6 n11
Answer:
9x-14
Step-by-step explanation:
7 times 2 is 14, and 5x plus 4x is 9x so it is 9x-14
Answer:
either 81 or 81.8
Step-by-step explanation:
No. The input a has multiple outputs
