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Bond [772]
3 years ago
12

Which ratio expresses the scale used to create this drawing? The camping site has dimensions of 15 meters by 60 meters.

Mathematics
2 answers:
tangare [24]3 years ago
5 0

Answer:

The answer is D on edg 2021

Neko [114]3 years ago
3 0

Answer:

Answer is d on edge 2021

Step-by-step explanation:

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If one of the angels of a triangle is 127 it’s called
KonstantinChe [14]

Answer:

obtuse triangle

Step-by-step explanation:

only one angle in a triangle has to be over 90 degrees for it to be and obtuse triangle

hoped this helped

7 0
3 years ago
There are 20 students In Marks class.Ten percent of the students in Marks homeroom class are also In art class.
poizon [28]

2 students are in art class

4 0
3 years ago
Suppose △JMN≅△KQR .
zvonat [6]
The positions of the letters must correspond. Appropriate choices are ...
  ∠M ≅ ∠Q
  QK ≅ MJ
  MN ≅ QR
4 0
3 years ago
Greatest to least 1/3 1/2 3/4
schepotkina [342]
The answer will be 3/4, 1/2, and 1/3.
The bigger the fraction the smaller it is.
So 3/4 would be first .
The smaller the fraction the bigger it is.
So 1/3 would be last.
So that leaves you with 1/2 so that one would be in the middle of the set.
So the answer would be...:3/4, 1/2, and 1/3.
Hope that helped.
4 0
3 years ago
For a binomial distribution with p = 0.20 and n = 100, what is the probability of obtaining a score less than or equal to x = 12
notsponge [240]
The binomial distribution is given by, 
P(X=x) =  (^{n}C_{x})p^{x} q^{n-x}
q = probability of failure = 1-0.2 = 0.8
n = 100
They have asked to find the probability <span>of obtaining a score less than or equal to 12.
</span>∴ P(X≤12) = (^{100}C_{x})(0.2)^{x} (0.8)^{100-x}
                    where, x = 0,1,2,3,4,5,6,7,8,9,10,11,12                  
∴ P(X≤12) = (^{100}C_{0})(0.2)^{0} (0.8)^{100-0} + (^{100}C_{1})(0.2)^{1} (0.8)^{100-1} + (^{100}C_{2})(0.2)^{2} (0.8)^{100-2} + (^{100}C_{3})(0.2)^{3} (0.8)^{100-3} + (^{100}C_{4})(0.2)^{4} (0.8)^{100-4} + (^{100}C_{5})(0.2)^{5} (0.8)^{100-5} + (^{100}C_{6})(0.2)^{6} (0.8)^{100-6} + (^{100}C_{7})(0.2)^{7} (0.8)^{100-7} + (^{100}C_{8})(0.2)^{8} (0.8)^{100-8} + (^{100}C_{9})(0.2)^{9} (0.8)^{100-9} + (^{100}C_{10})(0.2)^{10} (0.8)^{100-10} + (^{100}C_{11})(0.2)^{11} (0.8)^{100-11} + (^{100}C_{12})(0.2)^{12} (0.8)^{100-12}


Evaluating each term and adding them you will get,
P(X≤12) = 0.02532833572
This is the required probability. 
7 0
3 years ago
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