The answer I believe is 3.340kj.
Answer:
%H = 6.72 %
Explanation:
Percent composition of an element is the total mass of that element divided by the molecular mass of compound (or molecular mass) of which it is present in.
So,
Percent composition of Hydrogen will be given as,
%H = Total mass of H / Molecular Mass of Acetic Acid × 100
So,
Total Mass of H = 1.01 × 4 = 4.04 g
Molecular Mass of Acetic acid = 60.052 g/mol
Putting values in above formula,
%H = 4.04 g/mol ÷ 60.052 g/mol × 100
%H = 6.72 %
Answer:
76.25cm
Explanation:
38cm + 56cm +97cm +114cm = 305cm
305cm÷4 = 76.25cm
Answer : The ratio of the protonated to the deprotonated form of the acid is, 100
Explanation : Given,

pH = 6.0
To calculate the ratio of the protonated to the deprotonated form of the acid we are using Henderson Hesselbach equation :
![pH=pK_a+\log \frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
![pH=pK_a+\log \frac{[Deprotonated]}{[Protonated]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BDeprotonated%5D%7D%7B%5BProtonated%5D%7D)
Now put all the given values in this expression, we get:
![6.0=8.0+\log \frac{[Deprotonated]}{[Protonated]}](https://tex.z-dn.net/?f=6.0%3D8.0%2B%5Clog%20%5Cfrac%7B%5BDeprotonated%5D%7D%7B%5BProtonated%5D%7D)
As per question, the ratio of the protonated to the deprotonated form of the acid will be:
Therefore, the ratio of the protonated to the deprotonated form of the acid is, 100
Water. All organisms that depend on oxygen need water to live.