Answer:
0.00559 mol
Explanation:
The following data were obtained from the question:
V = 140mL = 0.14L
T = 296K
P = 98.2kPa = 98200Pa
Recall: 101325Pa = 1atm
98200Pa = 98200/101325 = 0.97atm
R = 0.082atm.L/Kmol
n =?
The number of mole (n) can be obtained as follows:
PV = nRT
n = PV /RT
n = (0.97x0.14)/(0.082x296)
n = 0.00559 mol
Therefore, the number of mole of the gas present is 0.00559 mol
Answer:
c a cold air mass and a warm air mass meet with neither moving
0.25 moles of CO2 is present in 11 grams of CO2.
Explanation:
A mole represents the number of chemical entities in an element or molecule.
Number of moles of an element or molecule is determined by the formula:
The Number of moles (n) = weight of the atom given ÷ atomic or molecular weight of the one mole of the element or molecule.
Themolar mass of one mole of carbon dioxide is:
12+ ( 16×2)
= 44 gram/mole
The given weight is 44 grams of carbon dioxide.
Putting the values in the equation,
n= 11 gms÷44 gms/ mole
n = 0.25 mole
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