Compare the electronegativity of H and O in the polar covalent bonds of a water

Chemistry

1 answer:

ExtremeBDS [4]2 years ago

7 0

Answer:

The O atom will tend to attract the electrons.

Explanation:

The electronegativity of O (3.5) is much higher than H (2.1), which means it is more likely to attract electrons. The higher the electronegativity, the more attractive.

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<h3>Answer:</h3>

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<h3>General Formulas and Concepts:</h3>

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Stoichiometry

Using Dimensional Analysis

<h3>Explanation:</h3>

Step 1: Define

[RxN - Balanced] 4NH₃ + 5O₂ → 4NO + 6H₂O

[Given] 13.2 mol O₂

Step 2: Identify Conversions

[RxN] 5 mol O₂ → 4 mol NO

Step 3: Stoich

[DA] Set up: $\displaystyle 13.2 \ mol \ O_2(\frac{4 \ mol \ NO}{5 \ mol \ O_2})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 10.56 \ mol \ NO$