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goblinko [34]
3 years ago
14

QUESTION 10

Chemistry
1 answer:
worty [1.4K]3 years ago
6 0
I have no idea honestly I don’t remember I had it and I forgot it
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Each of the following names is wrong. Draw structures based on them, and correct the names:(b) 1,1,1-trimethylheptane
devlian [24]

The correct IUPAC name of 1,1,1-trimethylheptane is 2,2-dimethyloctane.

<h3>IUPAC NAME:</h3>

It is systematic way of nomenclature of organic compounds.

It is based on the position of functional groups, preference of the functional group, long or short chain of carbon, preference of double bond, single and triple bond, branching of carbon chain, etc.

The given compound is 1,1,1-trimethylheptane.

The given name is wrong according to IUPAC name because the numbering of carbon atom should be done in that way in which the carbon atom chain is largest.

Here, in this case the numbering is done from right side. Thus the largest carbon chain have 8 carbon atom.

If the numbering is done according to the question, number of carbon atom in straight chain is 7.

Thus, we concluded that the Correct IUPAC name of 1,1,1-trimethylheptane is 2,2-dimethyloctane.

learn more about Nomenclature:

brainly.com/question/14094007

#SPJ4

5 0
2 years ago
Based on the methods used to separate the substance into its parts, is Substance U a compound?
dmitriy555 [2]

Answer: The answer is A

Explanation: No because it’s is a mixture because physical methods were used to separate its particals

3 0
3 years ago
Dinitrogen tetraoxide, N2O4, decomposes to nitrogen dioxide, NO2, in a first-order process. If k = 1.5 x 103 s-1 at 5 ºC and k =
Arada [10]

Answer:

The activation energy for the decomposition = 33813.28 J/mol

Explanation:

Using the expression,

\ln \dfrac{k_{1}}{k_{2}} =-\dfrac{E_{a}}{R} \left (\dfrac{1}{T_1}-\dfrac{1}{T_2} \right )

Wherem  

k_1\ is\ the\ rate\ constant\ at\ T_1

k_2\ is\ the\ rate\ constant\ at\ T_2

E_a is the activation energy

R is Gas constant having value = 8.314 J / K mol  

Thus, given that, E_a = ?

k_2=4.0\times 10^3s^{-1}

k_1=1.5\times 10^3s^{-1}  

T_1=5\ ^0C  

T_2=25\ ^0C  

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (5 + 273.15) K = 278.15 K  

T = (25 + 273.15) K = 298.15 K  

T_1=278.15\ K

T_2=298.15\ K

So,

\ln \frac{1.5\times 10^3}{4.0\times 10^3}\:=-\frac{E_{a}}{8.314}\times \left(\frac{1}{278.15}-\frac{1}{298.15}\right)

E_a=-\ln \frac{1.5\times \:10^3}{4.0\times \:10^3}\:\times \frac{8.314}{\left(\frac{1}{278.15}-\frac{1}{298.15}\right)}

E_a=-\frac{8.314\ln \left(\frac{1.5\times \:10^3}{4\times \:10^3}\right)}{\frac{1}{278.15}-\frac{1}{298.15}}

E_a=-\frac{689483.53266 \ln \left(\frac{1.5}{4}\right)}{20}

E_a=33813.28\ J/mol

<u>The activation energy for the decomposition = 33813.28 J/mol</u>

8 0
3 years ago
What does the slope of a distance vs time graph tell you? yes
bonufazy [111]

Answer:

an increase of acceleration or decrease of acceleration

Explanation:

5 0
3 years ago
Uses of photosynthesis products <br> what are the uses for the photosynthesis products
mario62 [17]

Answer:

uses of photosynthesies:

Explanation:

In photosynthesis ENERGY from light is used to convert CARBONDIOXDE and water into glucose and oxygen for 6 carbon and 6 water molecules, 1 glucosed and 6 oxygen molecules are produced.

3 0
3 years ago
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