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goblinko [34]
3 years ago
14

QUESTION 10

Chemistry
1 answer:
worty [1.4K]3 years ago
6 0
I have no idea honestly I don’t remember I had it and I forgot it
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An element like silicon is not usually used to make wires or pans because it?
svetlana [45]
It is not good conductors of electricity or heat!
5 0
3 years ago
What phases are most common at high temperatures
Nikitich [7]

Answer:

Liquids and gases.

For most substances, when heated to a high enough temperature, the molecules begin moving faster which results in its liquid or gas state.

5 0
3 years ago
A water solution is found to have a molar oh- concentration of 3.2 x 10-5. the solution would be classified as :_______.
Anuta_ua [19.1K]

A water solution is found to have a molar oh- concentration of 3.2 x 10-5. the solution would be classified as neutral.

The concentration of hydroxide ions (OH-) is measured by pOH. It is a way of expressing how alkaline a solution is. At 25 degrees Celsius, aqueous solutions with pOH values of 7 or less are neutral, whereas those with pOH values of 7 or more are acidic. The hydrogen ion potential is known as pH. The potential of hydroxide ions is known as pOH. 2. It is a scale used to estimate the hydrogen ion (H+) concentration in the solution. The hydroxide ion (OH-) concentration of the solution is measured using this scale.

pH + pOH = 14

 pOH = 3.2x 10-5

[OH-] = 10^(-pOH) =10^(- 3.2x 10-5)

= 0.99

7 0
2 years ago
What is the molarity of a 250.0 milliliter aqueous solution of sodium hydroxide that contains 15.5 grams of solute
tensa zangetsu [6.8K]

There are a number of ways to express concentration of a solution. This includes molarity. Molarity is expressed as the number of moles of solute per volume of the solution. The concentration of the solution is calculated as follows:

 <span> </span><span>Molarity = 15.5 g NaOH (1 mol NaOH / 40 g NaOH)  / .250 L solution</span>

<span>Molarity = 1.55 M</span>

5 0
3 years ago
For the titration of a weak acid with a strong base what is the pKa of the weak acid if the pH is 6.72 at the equilvalence point
Paladinen [302]

Explanation:

We have to calculate pK_{a} value.

It is known that at the equivalence point concentration of acid is equal to the concentration of anion formed.

Hence,         [HA] = [A^{-}]

Now, relation between pK_{a} and pH is as follows.

                   pH = pK_{a} + log \frac{[A^{-}]}{[HA]}

Putting the values into the above formula as follows.

                   pH = pK_{a} + log \frac{[A^{-}]}{[HA]}

                  4.23 = pK_{a} + log (1)            (as [HA] = [A^{-}])

                   pK_{a} = 4.23                (as log (1) = 0)

or,                   pK_{a} = 4

Thus, we can conclude that pK_{a} of given weak acid is 4.  

                   

6 0
3 years ago
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