2.4x+4.7(4x)=5936
Solve for x
X=280 standard version
4×280=1,120 high-quality version
Answer:
Step-by-step explanation:
If the engine torque y (in foot-pounds) of one model of car is given by y=−3.75x^2+23.2x+38.8
The engine speed is at maximum if dy/dx = 0
dy/dx = -2(3.75)x+23.2
dy/dx = -7.5x + 23.2
since dy/dx = 0
0 = -7.5x + 23.2
7.5x = 23.2
x = 23.2/7.5
x = 3.093
Hence the maximum torque is 3.09 rev/min
Each friend would get 3/4 of a sandwich.
We take the 8 sandwiches and decide them by six. Then we get 0.75. Then we change it to fractions.
0.75. 75
——- x 100 ——- Then we simplify.
1. 100. And get 3/4
Answer:
x=7
Step-by-step explanation:
