Answer:
C
Explanation:
I searched it online and it confirms my notes too
83.235 grams of CaCl2 is required to make 1 litre of 0.75M solution.
Explanation:
Molarity or molar concentration is the number of moles of solute that can be dissolved in 1 L of a solution.
let us find the number of moles
n=C*V Concentration is 0.75M
Volume is 1000ml.
n= 0.75*1
n= 0.75
This means there are 0.75 moles of CaCl2 in 1000 ml of solution of .75M.
Molar mass of CaCl2 is = 40.08+ 2(35.5)
= 110.98 gms
Thus 1 MOLE OF CaCl2 weighs 110.98
so 0.75 moles will weigh 110.98*0.75
= 83.235 grams of CaCl2 is required to make 1 litre of 0.75M solution.
Answer: The correct answer would be lactic acid fermentation.
Explanation:
In humans, specially in muscle cells, lactic acid fermentation takes place during high intensity exercise. During exercise when oxygen supply fails to meet the demands of muscle, they undergo lactic acid fermentation instead of cellular respiration.
During this process, the pyruvate (end product of glycolysis) is converted into the lactate with the help of enzyme lactate dehydrogenase.
It regenerates NAD⁺ lost in the glycolysis and thus, helps in continuous working of glycolysis.
Answer:
A: monomer
B: monomer
C: polymer
Explanation: <em> I just did it and it was right </em>
Answer:
Breakdown of Pyruvate
After glycolysis, pyruvate is converted into acetyl CoA in order to enter the citric acid cycle.
Explanation:
