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stepan [7]
2 years ago
14

Ted analyzes how much sugar is in 3 popular candy bars. He records the data on the line plot below.

Mathematics
1 answer:
Fiesta28 [93]2 years ago
4 0

Answer: 81 1/2

to determine the total amount of sugar we need to add

21 1/2 + 30 +30

^add the whole numbers the. add the fractions (21 +30+30) + (1/2)<<<

=81 + 1/2

which is equal to

81 1/2

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kari74 [83]
<span>100000 + 2000 + 500 + 150 + 17 +0.08

= 102000 + 500 + 150 + 17 + 0.08

= 102500 + 150 + 17 + 0.08

= 102650 + 17 + 0.08

= 102667 + 0.08

= 102667.08 <--</span>
7 0
3 years ago
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Pls show work or at least explain its essy but i need help
Hatshy [7]

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3 years ago
The score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.
Artemon [7]

Answer:

P(X \geq 74) = 0.3707

Step-by-step explanation:

We are given that the score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.

Let X = Score of golfers

So, X ~ N(\mu=73,\sigma^{2}=3^{2})

The z score probability distribution is given by;

           Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = population mean = 73

           \sigma = standard deviation = 3

So, the probability that the score of golfer is at least 74 is given by = P(X \geq 74)

 P(X \geq 74) = P( \frac{X-\mu}{\sigma} \geq \frac{74-73}{3} ) = P(Z \geq 0.33) = 1 - P(Z < 0.33)

                                               =  1 - 0.62930 = 0.3707                  

Therefore, the probability that the score of golfer is at least 74 is 0.3707 .

3 0
3 years ago
Equity in your home = fair market value - outstanding balance. If your home is worth $125,000 and you have an outstanding balanc
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Answer:

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Step-by-step explanation:

just subtract 125,000 by 36,000

although Its a guess

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ratelena [41]

Answer:

Step-by-step explanation:

The problem relates to filling 8 vacant positions by either 0 or 1

each position can be filled by 2 ways so no of permutation

= 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2

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b )

Probability of opening of lock in first arbitrary attempt

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c ) If first fails , there are remaining 255 permutations , so

probability of opening the lock in second arbitrary attempt

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