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stira [4]
3 years ago
10

Help help help help help

Mathematics
2 answers:
saw5 [17]3 years ago
7 0

Answer:

the answer would be 4m

hope this helped

Phantasy [73]3 years ago
7 0

Answer:

4m

Well there's 4 m's being added so to put it in simple terms, it would be 4m.

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Find the value of the variable and YZ if Y is between X and Z
PIT_PIT [208]
If point Y is between points X and Z, then

XY + YZ = XZ

In words, the distance from X to Y, plus the distance from Y to Z, is equal to the distance from X to Z. (See the attached picture.)

So 6b + 8b = 175

Can you finish it?


8 0
3 years ago
Read 2 more answers
Determine whether each statement is true or false. If false, give a counterexample.
bezimeni [28]
This statement is true, or else you wouldn't have a sphere.
7 0
3 years ago
I need help with this please
Ierofanga [76]
C is the correct answer


we should find the area of the square and then divide it by 24.
(360/15=24)


6 \times 6 \times \pi \times  \frac{1}{24}  = 36 \times \pi \times  \frac{1}{24}   \\  = 113.04 \times  \frac{1}{24}  = 4.71



good luck
8 0
3 years ago
Read 2 more answers
in the circl below, AD is diameter and AB is tangent at A. Suppose mADC=228*, find the measures of mCAB and mCAD. Type your nume
Andrew [12]

Given:

AD is diameter of the circle, AB is the tangent, and measure of arc ADC is 228 degrees.

To find:

The m\angle CAB and m\angle CAD.

Solution:

AD is diameter of the circle. So, the measure of arc AD is 180 degrees.

m(arcADC)=m(arcAD)+m(arcDC)

228^\circ=180^\circ+m(arcDC)

228^\circ-180^\circ+=m(arcDC)

48^\circ+=m(arcDC)

The measure inscribed angle is half of the corresponding subtended arc.

m\angle CAD=\dfrac{1}{2}\times m(arcDC)

m\angle CAD=\dfrac{1}{2}\times 48^\circ

m\angle CAD=24^\circ

AB is the tangent. So, m\angle BAD=90^\circ because radius is perpendicular on the tangent and the point of tangency.

m\angle BAD=m\angle CAB+m\angle CAD

90^\circ=m\angle CAB+24^\circ

90^\circ -24^\circ=m\angle CAB

66^\circ=m\angle CAB

Therefore, m\angle CAB=66^\circ and m\angle CAD=24^\circ.

4 0
2 years ago
Use substitution process to find x,y,and z from the equations 2x+4y+3z=14 , y+3z=11 , z=4
katen-ka-za [31]

Work backwards.

Start with z = 4.

Now deal with the middle equation

y + 3z = 11                    Substitute z = 4 and solve for y

y + 3(4) = 11                  Subtract 12 from both sides

y + 12 = 11

y + 12 - 12 = 11 -12         Combine terms on the left and right

y = - 1                             Now use the top equation for x

z = 4                              z still = 4

2x + 4(-1) +3(4) = 14

2x - 4 + 12 = 14              Solve 3z

2x + 8 = 14                     Subtract 8

2x + 8 - 8 = 14 - 8          Combine

2x = 6                            Divide by 2

x = 6/2

x = 3

Answer

x = 3

y = - 1

z = 4  

6 0
3 years ago
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