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xxMikexx [17]
3 years ago
15

When an atom of calcium (Ca) forms an ion by losing two electrons, what is the ion’s type and charge?

Chemistry
2 answers:
andre [41]3 years ago
8 0

The electrical charge of the calcium ion is +2.

posledela3 years ago
5 0

Answer:

cation +2

Explanation:

A cation is a positively charged ion, while an anion is a negatively charged ion. Contrary to how it sounds, when an atom loses electrons, it's charge becomes more positive. Since the calcium atom lost 2 electrons, it is a positive (+2) ion.

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What is one way scientists can split a substance into its simpler components
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Answer: By using electrolysis.

Explanation:

Electrolysis is a chemical change produced by sending an electric current through a compound. Electrolysis works because the hydrogen and oxygen ions are held together by an electric attraction.

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Which element has this electron configuration? <br> astatine<br> bromine<br> chlorine<br> fluorine
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What is it called when a gas is converted into a liquid
alex41 [277]
Your answer is probably
Vaporization point
3 0
3 years ago
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Explain why lithium is a strong reducing agent, whereas fluorine is a strong oxidizing agent.
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3 0
3 years ago
An ideal gas contained in a piston-cylinder assembly is compressed isothermally in an internally reversible process.
Tju [1.3M]

Answer:

a) \Delta S

b) entropy of the sistem equal to a), entropy of the universe grater than a).

Explanation:

a) The change of entropy for a reversible process:

\delta S=\frac{\delta Q}{T}

\Delta S=\frac{Q}{T}

The energy balance:

\delta U=[tex]\delta Q- \delta W

If the process is isothermical the U doesn't change:

0=[tex]\delta Q- \delta W

\delta Q= \delta W

Q= W

The work:

W=\int_{V1}^{V2}P*dV

If it is an ideal gas:

P=\frac{n*R*T}{V}

W=\int_{V1}^{V2}\frac{n*R*T}{V}*dV

Solving:

W=n*R*T*ln(V2/V1)

Replacing:

\Delta S=\frac{n*R*T*ln(V2/V1)}{T}

\Delta S=n*R*ln(V2/V1)}

Given that it's a compression: V2<V1 and ln(V2/V1)<0. So:

\Delta S

b) The entropy change of the sistem will be equal to the calculated in a), but the change of entropy of the universe will be 0 in a) (reversible process) and in b) has to be positive given that it is an irreversible process.

7 0
3 years ago
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