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Ugo [173]
2 years ago
15

How many moles are in 10 mg of NO2

Chemistry
2 answers:
podryga [215]2 years ago
4 0

mole=10 x 10⁻³ : 46 g/mol = 2.17 x 10⁻⁴

IgorC [24]2 years ago
3 0
We have to convert 10 mg to g first

10mg x (g / 10^3 mg) = 10 x 10^-3 g
Once we have the mass in grams, we can use the relationship of g/mol and use molar mass of NO2 to solve

10 x 10^-3 g x (mol NO2 / 46 g NO2) = 2.17 x 10^-4 mol NO2

Answer is 2.17 x 10^-4 mol NO2
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M₁=the starting concentration of the solution (in this case 2.6M)
V₁=the starting volume of the solution (in this case 0.035L)
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Explaining the reasoning behind the above equation:
MV=moles of solute (in this case KCl) because molarity is the moles of solute per Liter of solution so by multiplying the molarity by the volume you are left with the moles of solute.  The moles of solute is a constant since by adding solvent (in this case water) the amount of solute does not change.  That means that M₁V₁=moles of solute=M₂V₂ and that relationship will always be true in any dilution.

Solving for the above equation:
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 Second, Finding the amount of water needed to be added:
Since we know that the volume of the solution was originally 35mL and needed to be diluted to 75.8mL to reach the desired molarity, to find the amount of solvent needed to be added all you do is V₂-V₁ since the difference in the starting volume and final volume is equal to the volume of solvent added.
75.8mL-35mL=40.8mL
40.8mL of water needs to be added

I hope this helps.  Let me know if anything is unclear.
Good luck on your quiz!
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