Answer:
i don't know i thought it was 2 different answers
Step-by-step explanation:
Answer:
![x=4y^2-24y+30](https://tex.z-dn.net/?f=x%3D4y%5E2-24y%2B30)
![(x-4.5)^2+(y-2.5)^2=23](https://tex.z-dn.net/?f=%28x-4.5%29%5E2%2B%28y-2.5%29%5E2%3D23)
Step-by-step explanation:
Standard form of a sideways parabola: ![x=ay^2+by+c](https://tex.z-dn.net/?f=x%3Day%5E2%2Bby%2Bc)
Given equation:
![4y^2-x-24y+30=0](https://tex.z-dn.net/?f=4y%5E2-x-24y%2B30%3D0)
Add x to both sides:
![4y^2-24y+30=x](https://tex.z-dn.net/?f=4y%5E2-24y%2B30%3Dx)
![\implies x=4y^2-24y+30](https://tex.z-dn.net/?f=%5Cimplies%20x%3D4y%5E2-24y%2B30)
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<u>Standard form of circle equation</u>
![(x-a)^2+(y-b)^2=r^2](https://tex.z-dn.net/?f=%28x-a%29%5E2%2B%28y-b%29%5E2%3Dr%5E2)
(where (a,b) is the center and r is the radius)
Given equation:
![2x^2+2y^2-18x-10y+7=0](https://tex.z-dn.net/?f=2x%5E2%2B2y%5E2-18x-10y%2B7%3D0)
Group like terms:
![2x^2-18x+2y^2-10y+7=0](https://tex.z-dn.net/?f=2x%5E2-18x%2B2y%5E2-10y%2B7%3D0)
Divide by 2:
![x^2-9x+y^2-5y+3.5=0](https://tex.z-dn.net/?f=x%5E2-9x%2By%5E2-5y%2B3.5%3D0)
Factor by completing the square for each variable:
![(x-4.5)^2-20.25+(y-2.5)^2-6.25+3.5=0](https://tex.z-dn.net/?f=%28x-4.5%29%5E2-20.25%2B%28y-2.5%29%5E2-6.25%2B3.5%3D0)
Rearrange into standard form:
![(x-4.5)^2+(y-2.5)^2=23](https://tex.z-dn.net/?f=%28x-4.5%29%5E2%2B%28y-2.5%29%5E2%3D23)
Therefore, the circle has a center at (4.5, 2.5) and a radius of √23
Answer:
Step-by-step explanation:
you can figure out the area by using two formulas: area of a circle (on each end are two semi circles which when combined, make a circle) and area of a rectangle
Acircle: pi(r^2) = pi(5^2) = 25pi
Arectangle: length*width = 20*10 = 200ft^2
area of composite figure: (25pi ft^2) + 200ft^2
Answer:
4
Step-by-step explanation:
do the math plug it in
4 + 6 = 10,
10 x 2 = 20
20/5 = 4