Consider the chemical reaction in equilibrium.

H2(g)+I2(s)→HI(s)H2(g)+I2(s)→HI(s) balance equations

poizon [28]

Answer:

H2(g)+I2(s)→2HI(s)

Explanation:

Hello there!

In this case, according to the given information and unbalanced chemical reaction, we infer it must be balanced in agreement with the law of conservation of mass because the reactants side has two hydrogen and iodine atoms whereas the products side has just one. In such a way, by placing a 2 on HI, we obtain the following balanced reaction:

H2(g)+I2(s)→2HI(s)

Regards!

5 0

3 years ago

The strong nuclear force is always smaller than the electrostatic force true or false

emmasim [6.3K]

Answer:

False

Explanation:

The Strong Nuclear Force is defined as an attractive force between neutrons and protons which is responsible to hold the nucleus together.

Electrostatic force is the repulsive or attractive force between two electrically charged objects.

Strong nuclear force is always greater than electrostatic force but changes with the distance. Strong nuclear attraction keeps the nucleus of an atom together in a small space as well which is stronger than their electrostatic repulsion.

it is said that, the strong nuclear force is the strongest force in the universe.

Hence, the given statement is false.

5 0

3 years ago

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6. Under standard-state conditions, what spontaneous reaction will occur in aqueous solution among the ions Ce4+, Ce3+, Fe3+, an

xz_007 [3.2K]

Answer:

ΔG° = -80.9 KJ

Assuming this reaction takes place at room temperature (25 °C):

K= $1.53x10^{14}$

Explanation:

1) Reduction potentials

First of all one should look up the reduction potentials for the species envolved:

$Ce^{4+} + e$ → $Ce^{3+}$ E°red=1.61V

$Fe^{3+} + e$ → $Fe^{2+}$ E°red=0.771V

2) Redox pair

Knowing their reduction pontentials one can determine a redox pair: one species must oxidate while the other is reducing. <u>Remember: the table gives us the reduction potential, so if we want to know the oxidation potential all that has to be done is reverce the equation and change the potencial signal (multiply to -1).</u>

1) $Ce^{4+}$ reduces while $Fe^{2+}$ oxidates

(oxidation) $Fe^{2+}$ → $Fe^{3+} + e$ E°oxi=-0.771V

(reduction) $Ce^{4+} + e$ → $Ce^{3+}$ E°red=1.61V

(overall equation) $Fe^{2+}+Ce^{4+}$ → $Ce^{3+}+Fe^{3+}$ E°=Ereduction + Eoxidation= 1.61 v+(-0.771 v) = 0.839v

The cell potential can also be calculated as the cathode potencial minus the anode potential:

E° = E cathode - E anode =1.61 v - 0.771 v=0.839 v

3) Gibbs free energy and Equilibrium constant

ΔG°=-nFE°, where 'n' is the number of electrons involved in the redox equation, in this case n is 1. 'F' is the Faraday constant, whtch is 96500 C. E° is the standard cell potencial.

ΔG°=-nFE°=-1*96500*0.839

ΔG° = - 80963 J = -80.9 KJ

The Nerst equation gives us the relation of chemical equilibrium and Electric potential.

E=E°- $\frac{RT}{nF} Ln Q$

Where 'R' is the molar gas constant (8.314 J/mol)

It's known that in the equilibrium E=0, so the Nerst equation, at equilibrium, becomes:

E°= $\frac{RT}{nF} Ln K$

Isolating for 'K' gives:

$K=e^{\frac{nFE^{o} }{RT} }$

This shows that 'K' is a fuction of temperature. Assuming this reaction takes place at room temperature (25 °C):

K= $1.53x10^{14}$

6 0

4 years ago

What did most people assume the earth was at the center of?

Gala2k [10]

Center of the solar system

4 0

3 years ago

Read 2 more answers

desicribe the relationship between an inner planets distance from the sun and its period of revolution?

Anit [1.1K]

Kepler’s third law exhibits the relationships between the distance of a planet from the sun and the period of its revolution. Kepler’s third law is also sometimes referred to as the law of harmonies.

Kepler’s third law compares the orbital period and the radius of an orbit of a planet to the distance of the planet to the sun. It states mathematically that the more distant a planet is from the sun the greater its orbital period will be. The period of revolution of a planet is measured in days, weeks, months or years. For example, Earth’s period of revolution is 365 days.

6 0

3 years ago