Answer:
Here's what I get.
Explanation:
The name tells me the compound is a lactone (a cyclic ester).
1. IR spectrum
1770 cm⁻¹
Esters and unstrained lactones normally absorb at 1740 cm⁻¹.
This peak is shifted to a higher frequency by ring strain.
A five-membered lactone absorbs at 1765 cm⁻¹, and a four-membered lactone at 1840 cm⁻¹.
The compound is probably a five-membered lactone.
2. NMR spectrum
2.28 m (2H)
2.48 t (2H)
4.35 t (2H)
This indicates three CH₂ groups arranged as X-CH₂-CH₂-CH₂-Y.
The X-CH₂- and -CH₂-Y signals would each be triplets, being split by the central -CH₂- group.
The central -CH₂- signal would be a multiplet, split by the non-equivalent hydrogens on either side.
The peak at 4.35 ppm indicates that the group is adjacent to an oxygen atom ( -CH₂- = 1.3; -CH₂-O- = 3.3 - 4.5).
The peak at 2.42 ppm indicates that the group is adjacent to a carbonyl group (-CH₂-C=O = 1.8 - 2.5.
The only way to fit these pieces together is if γ-butyrolactone has the structure shown below.
Confirmation:
(a) The IR spectrum shows a carbonyl peak at 1770 cm⁻¹.
(b) The NMR spectrum matches that given in the problem.
They are more attracted by the oxygen atom than by the hydrogen atom.
Explanation:
In the polar bond of water which is made up of hydrogen and oxygen atoms, the shared electrons are more attracted by the oxygen atom than by the hydrogen atom.
The interatomic bond in water is a polar covalent bond.
In this bond type, two species shares their valence electrons.
The bond usually occurs between non-metals with an electronegativity difference that is small.
Oxygen is more electronegative compared to hydrogen.
- This implies that oxygen pulls the electron more closely to itself since it has a greater affinity.
- This leaves a partial negative charge on oxygen and a positive charge on hydrogen.
- The molecule is said to be polar covalent.
learn more:
Covalent bond brainly.com/question/5258547
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<u>Answer</u>
So this is the reaction that happens.
<span>C4H10 + O2 = CO2 + H2O </span>
<span>Balanced, it is </span>
<span>2C4H10 + 8O2 = 8CO2 + 10H2O </span>
<span>Given 1 kg or 1000 g of butane, use stoichiometry aka factor labeling aka conversions and mole ratios to get to grams of oxygen. </span>
<span>I'll do an example. Let's form water. Hydrogen is diatomic too. </span>
<span>2H2 + O2 = 2H2O </span>
<span>Given 1000 g of Hydrogen, I need to know how many grams of oxygen to use. To convert grams to moles,
I know that 1 mol of H2 equals 2.02 g. Then, for every mole of O2, there are 2 moles of H2. Then converting moles of O2 to grams, I know that one mole of it equals 32 grams. </span>
<span>[1000 g H2] x [1 mol H2/2.02 g H2] x [1 mol O2/2 mol H2] x [32 g O2/1 mol O2] </span>
<span>My answer would be 7.9 kg </span>
Answer:
yuh
Explanation:
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