Volume of solute = 250 * 2%
= 250 * 0.02
= 5
In short, Your Answer would be 5 mL
Hope this helps!
<h3>
Answer:</h3>
3.5 Newton
<h3>
Explanation:</h3>
We are given;
Mass of the ball = 140 g
Acceleration = 25 m/s²
Required to find the force;
- According to Newton's second law of motion, the resultant force on a body in motion and the rate of change in linear momentum are directly proportional.
- That is;

- Thus; F = ma , where F is the resultant force, m is the mass and a is the acceleration.
To get the force we substitute the value of m and a in the formula;
Therefore;
F = 0.14 kg × 25 m/s²
= 3.5 N
Hence, the force needed to accelerate the ball is 3.5 N
B is the answer
I double checked hope it helps
Answer:
The answer to your question is 0.113 moles of Fe₂O₃
Explanation:
Data
moles of Fe₂O₃ = ?
mass of Fe₂O₃ = 18 grams
Process
1.- Calculate the molar mass of Fe₂O₃
Fe₂O₃ = (56 x 2) + (16 x 3)
= 112 + 48
= 160 g
2.- Use proportions to solve this problem. The molar mass is equivalent to 1 mol.
160 g of Fe₂O₃ --------------- 1 mol
18 g of Fe₂O₃ ---------------- x
x = (18 x 1)/160
x = 0.113 moles of Fe₂O₃