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Strike441 [17]
4 years ago
13

2CH2(g) + 50 (g) → 400/(g) + 2 H2O(g)

Chemistry
1 answer:
Nadusha1986 [10]4 years ago
6 0

168.96 g of carbon dioxide (CO₂)

Explanation:

The chemical reaction representing the combustion of acetylene:

2 C₂H₂ (g) + 5 O₂ (g)→ 4 CO₂ (g) + 2 H₂O (g)

number of moles = mass / molecular weight

number of moles of acetylene (C₂H₂) = 50 / 26 = 1.92 moles

Taking in account the stoichiometry of the chemical reaction, we devise the following reasoning:

if       2 moles of acetylene (C₂H₂) produces 4 moles of carbon dioxide (CO₂)

then 1.92 moles of acetylene (C₂H₂) produces X moles of carbon dioxide (CO₂)

X = (1.92 × 4) / 2 = 3.84 moles of carbon dioxide (CO₂)

mass = number of moles × molecular weight

mass of carbon dioxide (CO₂) = 3.84 × 44 = 168.96 g

Learn more about:

combustion of hydrocarbons

brainly.com/question/4919676

brainly.com/question/1406903

#learnwithBrainly

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5 0
3 years ago
In the reaction of silver nitrate with copper metal, metallic silver comes out of solution, and the solution turns blue. This as
aalyn [17]

Answer:

Single displacement reaction.

Explanation:

Hello!!

In this case, since the reaction between silver nitrate and copper metal is:

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As silver was forming silver nitrate, due to the presence of copper, which has the capacity to displace silver out of the salt, we notice the formation of solid silver and a resulting copper (II) nitrate which is blue in aqueous solution.

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7 0
3 years ago
A chemistry student needs of acetic acid for an experiment. He has available of a w/w solution of acetic acid in acetone. Calcul
Volgvan

Answer:

49.4 g Solution

Explanation:

There is some info missing. I think this is the original question.

<em>A chemistry student needs 20.0g of acetic acid for an experiment. He has 400.g  available of a 40.5 %  w/w solution of acetic acid in acetone.  </em>

<em> Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button. Round your answer to 3 significant digits.</em>

<em />

We have 400 g of solution and there are 40.5 g of solute (acetic acid) per 100 grams of solution. We can use this info to find the mass of acetic acid in the solution.

400gSolution \times \frac{40.5gSolute}{100gSolution} = 162 g Solute

Since we only need 20.0 g of acetic acid, there is enough of it in the solution. The mass of solution that contains 20.0 g of solute is:

20.0gSolute \times \frac{100gSolution}{40.5gSolute} = 49.4g Solution

4 0
3 years ago
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4 years ago
Which one of the following compounds is insoluble in water?
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7 0
3 years ago
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