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Strike441 [17]
3 years ago
13

2CH2(g) + 50 (g) → 400/(g) + 2 H2O(g)

Chemistry
1 answer:
Nadusha1986 [10]3 years ago
6 0

168.96 g of carbon dioxide (CO₂)

Explanation:

The chemical reaction representing the combustion of acetylene:

2 C₂H₂ (g) + 5 O₂ (g)→ 4 CO₂ (g) + 2 H₂O (g)

number of moles = mass / molecular weight

number of moles of acetylene (C₂H₂) = 50 / 26 = 1.92 moles

Taking in account the stoichiometry of the chemical reaction, we devise the following reasoning:

if       2 moles of acetylene (C₂H₂) produces 4 moles of carbon dioxide (CO₂)

then 1.92 moles of acetylene (C₂H₂) produces X moles of carbon dioxide (CO₂)

X = (1.92 × 4) / 2 = 3.84 moles of carbon dioxide (CO₂)

mass = number of moles × molecular weight

mass of carbon dioxide (CO₂) = 3.84 × 44 = 168.96 g

Learn more about:

combustion of hydrocarbons

brainly.com/question/4919676

brainly.com/question/1406903

#learnwithBrainly

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The half-life of phosphorus-32 is 14.30 days. how many milligrams of a 20.00 mg sample of phosphorus-32 will remain after 85.80
ZanzabumX [31]
The amount of sample that is left after a certain period of time, given the half-life, h, can be calculated through the equation.

             A(t) = A(o) (1/2)^(t/d)

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             A(t) = (20 mg)(1/2)^(85.80/14.30)

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Hence, the answer is 0.3125 mg. 
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3 years ago
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20.00 g of aluminum (al) reacts with 78.78 grams of molecular chlorine (cl2) all of each reactant is completely consumed and a s
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The word equation is

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CH3COOH(aq) + NaOH(aq) → H2O(l) + NaCH3COO(aq)
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