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kirza4 [7]
3 years ago
10

Deduce the relation between kwh and joule define 1 watt​

Physics
1 answer:
dimulka [17.4K]3 years ago
5 0

Explanation:

We know that kWh is a commercial unit of energy.

Also, 1 Joule = 1 watt × 1 seconds

1\ kWh=1kW \times 1\ h

Since ,1 h = 3600 s and 1kW = 1000 W

1\ kWh=1000\ W \times 3600\ s\\\\1\ kWh = 36\times 10^5\ W-s\\\\1\ kWh=36\times 10^5\ J

So, the relation is : 1\ kWh=36\times 10^5\ J

1 watt is defined as the power of an appliance when the energy is transferred at a rate of 1 Joule per second.

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A particle has 37.5 J of kinetic energy and 12.5 J of gravitational potential energy at one point during its fall from a tree to
Varvara68 [4.7K]

Answer: 50J

Explanation:

Mechanical energy follows the same principles of kinetic energy and potential energy, it is conserved. So Ei = Ef.

Mechanical energy is the sum of ALL energy's. There is no friction, so its just kinetic plus potential.

37.5 + 12.5 = 50J

Since the particle has not touched the ground, it has not transferred any energy to the ground yet, therefore the mechanical energy must still be 50J; mostly in kinetic energy with a very small amount of potential because of the low height relative to the ground.

3 0
3 years ago
A mountain lion jumps to a height of 3.25 m when leaving the ground at an angle of 43.2°. What is its initial speed (in m/s) as
miss Akunina [59]

Recall that

{v_f}^2={v_i}^2+2a\Delta y

where v_i and v_f are the lion's initial and final vertical velocities, a is its acceleration, and \Delta y is the vertical displacement.

At its maximum height, the lion has 0 vertical velocity, so we have

0={v_i}^2-2gy_{\rm max}

where <em>g</em> is the acceleration due to gravity, 9.80 m/s², and we take the starting position of the lion on the ground to be the origin so that \Delta y=y_{\rm max}-0=y_{\rm max}.

Let <em>v</em> denote the initial speed of the jump. Then

v_i=v\sin(43.2^\circ)=\sqrt{2\left(9.80\dfrac{\rm m}{\mathrm s^2}\right)(3.25\,\mathrm m)}\implies\boxed{v\approx11.7\dfrac{\rm m}{\rm s}}

6 0
3 years ago
3. Do you think Lynn’s (the protagonist)actions were justifiable by her motives? Why or why not? Please help me Bad Genius the m
nekit [7.7K]

Answer:

I do believe her actions were justified.

Explanation:

Due to the school charging extra fee from her father who makes a modest amount as a teacher. There was sum of money involved that could change how he lived and her.

I do not believe her actions where justified

She had a lot going for her. She could have skipped the hardship of helping grace and pass. She could have easily have gotten a good job with a degree and paid back all the debts owed. Alot of troubles could have been avoided just by doing her own thing.

7 0
3 years ago
A river with a flow rate of 7 m3/s discharges into a lake with a volume of 9,000,000 m3. The concentration of a particular VOC i
soldi70 [24.7K]

Answer:

The concentration downstream reduces to 0.03463mg/L

Explanation:

Initially let us calculate the time it is required to fill the lake, since for that period of time the pollutant shall remain in the lake before being flushed out.

Thus the detention period is calculated as

t=\frac{V}{Q}\\\\t=\frac{9000000}{7}=1.285\times 10^{6}seconds\\\\\therefore t = 14.872days

Now the concentration of the pollutant after 14.872 days is calculated as

N_{t}=N_{0}e^{-kt}

where

N_{o} is the initial concentration

't' is the time elapsed after which the remaining concentration is calculated

k is the dissociation constant.

Applying values we get

N_{t}=3\times e^{-0.3\times 14.872}

N_{t}=0.03463mg/L

4 0
3 years ago
The engine in an imaginary sports car can provide constant power to the wheels over a range of speeds from 0 to 70 miles per hou
kirill115 [55]

Answer:

Part A

it would take 6 sec

it would take 3 sec

Explanation:

We are told that the power supplied to the wheel is constant which means that the sport car is gaining energy i.e

                           power \ \alpha  \ energy

Hence if power is constantly supplied energy constantly increase

From the formula of the Kinetic energy

                       KE  = \frac{1}{2} mv^2

we can see that as the speed doubles from 29 mph  to 58 mph  the energy needed is 2^2 = 4 times of the energy from the formula

   Also the time needed would also be 4 times because energy i directly proportional to time

       Hence to reach 58mph the time that it would take is

                          = 4* 1.5sec = 6sec

     

We are told that the ground pushes the car  with a constant force and

                 F = ma

this means that the acceleration is also constant

             now from newtons law

     v = u +at  

 Looking at it we see that final velocity is directly proportional with time

hence it would take twice the time to reach twice the final velocity

        Time to reach 58mph = 3 s

        since time to reach 29 mph(\frac{1}{2} \ of \ [58mph]) =( \frac{1}{2} \ of \ 3sec )1.5 s

6 0
3 years ago
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