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Reika [66]
2 years ago
7

How should you plan to excercise if you want to remain healthy past the age of 65

Physics
2 answers:
gayaneshka [121]2 years ago
5 0
Run,karate,aerobic exercise
Helen [10]2 years ago
3 0

Explanation:

by taking a brisk walking about 150 minutes

2 days a week exercise that strengths muscles

drinking water

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Lila is a track and field athlete. She must complete four laps around a circular track. The track itself is a 400 meter track an
Aleonysh [2.5K]

Answer:

Her speed is 1.1 m/s, and her velocity is 0 m/s

Explanation:

Speed = Distance covered/Time

Given

Distance = 400m

Time = 6minutes = 6*60 = 360 secs

Substitute the given parameter into the formula;

Speed = 400/360

Speed = 1.1m/s

Since the track is a circular track, the displacement will be zero. She is only moving in a circular path (no direction)

Velocity = Displacement/Time

Velocity = 0/3600

Velocity = 0m/s

Hence her speed is 1.1 m/s, and her velocity is 0 m/s

6 0
3 years ago
A remote-controlled car is moving in a vacant parking lot. The velocity of the car as a function of time is given by υ⃗ =[5.00m/
Reptile [31]
It would possibly be [7.00m/s(0.5613m/s)
8 0
3 years ago
A current of 3.75 A in a long, straight wire produces a magnetic field of 2.61 μT at a certain distance from the wire. Find thi
Bad White [126]

Given :

Current, I = 3.75 A .

Magnetic Field, B = 2.61\times 10^{-4}\ T

To Find :

The distance from the wire.

Solution :

We know,

B = K\dfrac{2i}{d}\\\\d = 10^{-7}\times \dfrac{2\times 3.75}{2.61\times 10^{-4}}\\\\d =  0.00287\ m \\\\d = 2.87\times 10^{-3}\ m

Hence, this is the required solution.

5 0
3 years ago
A light bulb emits light that travels uniformly in all directions. Detailed measurements show that at a distance of 56 m from th
vladimir1956 [14]

Complete question:

A light bulb emits light that travels uniformly in all directions. Detailed measurements show that at a distance of 56 m from the bulb, the amplitude of the electric field is 3.78 V/m. What is the average intensity of the light?

Answer:

The average intensity of the light is 0.02 W/m²

Explanation:

Given;

Amplitude of the electric field, E₀ = 3.78 V/m

The average intensity of the light is calculated as follows;

I_{avg} = \frac{c\epsilon_0 E_0^2}{2}

where;

I_{avg} is the average intensity of the light

c is speed of light = 3 x 10⁸ m/s

I_{avg} = \frac{(3\times 10^8)(8.85 \times 10^{-12}) (3.78)^2}{2} \\\\I_{avg} = 0.01897 \ W/m^2\\\\I_{avg} = 0.02 \ W/m^2

Therefore, the average intensity of the light is 0.02 W/m²

4 0
3 years ago
In 1993, the gold reserves in the United States were about 8.490 x 10^6
lorasvet [3.4K]
  • Mass of gold :-8.490×10⁶kg
  • Density=19300kg/m³

Volume?

Let's see

Volume:-

  • Mass/Density
  • 8.49×10⁶/19300
  • 0.000439×10⁶
  • 439m³
6 0
2 years ago
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