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3 years ago

Can it perform algebra

Mathematics

1 answer:

Ronch [10]3 years ago

6 0

Can what perform algebra?

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Shirts are on sale 20% off! The original price of the shirt was $28.50. How

loris [4]

Answer: im not sure

Step-by-step explanation:

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3 years ago

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6cos(20πt-π)+6√3cos(20πt-π\2)

juin [17]

Answer:

Answer is -6t

Step-by-step explanation:

${ \tt{ = (6 \cos(20\pi t) \cos(\pi) + 6\sin(20\pi t) \sin(\pi) ) + 6 \sqrt{3} ( \cos(20\pi t) \cos( \frac{\pi}{2} ) + \sin(20\pi t) \sin( \frac{\pi}{2} )) }} \\ = { \tt{ (- 6t + 0) + (0 + 0)}} \\ = { \tt{ - 6t}}$

Note that π is 180°

5 0

3 years ago

After the party, 3 1⁄4 pecan pies remained. The next day, Edward's family ate 1 1⁄4 of a pie. How many pecan pies were left?

vlabodo [156]

Answer:

Step-by-step explanation:

Because 3-1 is 2 and 1/4-1/4=0

So 2

4 0

3 years ago

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An apartment complex on Ferenginar with 250 units currently has 223 occupants. The current rent for a unit is 892 slips of Gold-

Triss [41]

Answer:

Step-by-step explanation:

Given data

Total units = 250

Current occupants = 223

Rent per unit = 892 slips of Gold-Pressed latinum

Current rent = 892 x 223 =198,916 slips of Gold-Pressed latinum

After increase in the rent, then the rent function becomes

Let us conside 'y' is increased in amount of rent

Then occupants left will be [223 - y]

Rent = [892 + 2y][223 - y] = R[y]

To maximize rent =

$\frac{dR}{dy}=0\\=2(223-y)-(892+2y)=0\\=446-2y-892-2y=0\\=-446-4y=0\\y=\frac{-446}{4}=-111.5$

Since 'y' comes in negative, the owner must decrease his rent to maximixe profit.

Since there are only 250 units available;

$y=-250+223=-27\\\\maximum \,profit =[892+2(-27)][223+27]\\=838 * 250\\=838\,for\,250\,units$

Optimal rent - 838 slips of Gold-Pressed latinum

8 0

3 years ago

Consider the limit of rational function p(x)l q(x)

Helga [31]

$\\ \sf\bull\dashrightarrow {\displaystyle{\lim_{x\to c}}}\dfrac{p(x)}{q(x)}=\dfrac{0}{1}=0$

The limit tends to 0
Hence c=0

$\\ \sf\bull\dashrightarrow {\displaystyle{\lim_{x\to c}}}\dfrac{p(x)}{q(x)}=\dfrac{1}{1}=1$

Here limit tends to 1
Hence c=1

$\\ \sf\bull\dashrightarrow {\displaystyle{\lim_{x\to 0}}}\dfrac{p(x)}{q(x)}=\dfrac{1}{0}=\infty$

Here x tends to infty.
c=infty

For the fourth one limit also tends to zero

8 0

3 years ago