X=width of a coccer pitch
2x-20=length of a soccer pitch
Area (rectangule)=length x width
We suggest this equation:
x(2x-20)=6000
2x²-20x=6000
2x²-20x-6000=0
x²-10x-3000=0
We solve this quadratic equation:
x=[10⁺₋√(100-4*1*-3000)]/2=[10⁺₋√(100+12000)]/2=
=(10⁺₋110)/2
we have two solutions:
x₁=(10-110)/2=-50, invalid solution.
x₂=(10+110)/2=60
x=60
2x-20=2(60)-20=120-20=100
Solution: the length is 100 m, and the width is 60 m.
To check:
Area=100 m*60 m=6000 m²
The twice of width is =2(60 m)=120 m,
20 m less than twice its width is: 120 m-20 m=100 m=the length.
Answer:
10 inches
Step-by-step explanation:
18*2=36
56-36=20
20/2= 10
The missing side length is 10 inches.
Hope this helps! Have a nice day :)
Answer:
hello,
the answer is option c (0.84)
and if you wabt to find in angle then the answer is 33.04°.
<em><u>hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
I think that 52 is next number
Answer:
4A/ (πa) = b
Step-by-step explanation:
A = πab/4
Multiply each side by 4
4A = 4πab/4
4A = πab
Divide each side by πa
4A/(πa) = πab/ πa
4A/ (πa) = b
