Distance southward = 6x = 400, so x=66.66
total distance = 7x+x=8x = 533.33m
Answer:
the upper left Quadrant is Quadrant II
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>⤴</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em>
Answer:
The correct answer is 15 cm.
Step-by-step explanation:
Let the width of the required poster be a cm.
We need to have a 6 cm margin at the top and a 4 cm margin at the bottom. Thus total margin combining top and bottom is 10 cm.
Similarly total margin combining both the sides is (4+4=) 8 cm.
So the required printing area of the poster is given by {( a-10 ) × ( a - 8) } 
This area is equal to 125
as per as the given problem.
∴ (a - 10) × (a - 8) = 125
⇒
- 18 a +80 -125 =0
⇒
- 18 a -45 = 0
⇒ (a-15) (a-3) = 0
By law of trichotomy the possible values of a are 15 and 3.
But a=3 is absurd as a
4.
Thus the required answer is 15 cm.
I am pretty sure your answer will be 96783564.8, but it may need to be rounded. If I am wrong, I am sorry.
Hope this helps~!