The mass change, or the mass defect, can be calculated by the formula that is very known to be associated with Albert Einstein.
E = Δmc²
where
E is the energy gained or released during the reaction
c is the speed of light equal to 3×10⁸ m/s
Δm is the mass change
(1.715×10³ kJ)(1,000 J/1 kJ) = Δm(3×10⁸ m/s)²
Δm = 1.91×10⁻¹¹ kg
Answer:
V₂ = 1.5 L
Explanation:
Given data:
Initial volume of balloon = 1.76 L
Initial temperature = 295 K
Final temperature = 253.15 K
Final volume = ?
Solution:
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 1.76 L ×253.15 K / 295 K
V₂ = 445.54 L.K /295 K
V₂ = 1.5 L
Calculations in chemistry can range from large numbers to the smallest number in decimals to be more accurate in data results. When this occurs using scientific notations allows you to note down results regardless of size as accurate as possible without writing a lot of numbers.
Answer:
640.32 g
Explanation:
2KClO₃ → 2KCl + 3O₂
First we <u>convert KClO₃ moles to O₂ moles,</u> using the <em>stoichiometric coefficients</em>:
- 13.34 mol KClO₃ *
= 20.01 mol O₂
Then we <u>convert O₂ moles to grams</u>, using its <em>molar mass</em>:
- 20.01 mol O₂ * 32 g/mol = 640.32 g
So 640.32 g of O₂ are formed from 13.34 moles of KClO₃.
