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3 years ago

What is a potential problem with respect to the timing for when a cytotoxic?

1 answer:

7 0

Cytotoxic is a characteristic of a medicine that bears the ability to cure cancer. The timing of the medication is very important because if not used properly, the substance or the drug may damage also even the healthy cells. Thus, it is just right to caution everyone, especially those who are involved, with the right usage of the drug.

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What is the number of moles of solute in 250 mL of a 0.4 M solution?

mafiozo [28]

Answer:

0,1 mol

Explanation:

We know that the formula of concentration is C= moles of solute/ volume

0,4 M= moles of solute/ 250 mL

Convert mL to L 250 mL =0,25 L

0,4 M x 0,25 L= moles of solute

0,1 moles= moles of solute

3 0

3 years ago

Each square of the periodic table shows information about one element. The square usually shows the element's

omeli [17]

D, all of the above.

7 0

3 years ago

Why can’t you perform single displacement reactions with group IA metals?

pishuonlain [190]

Answer is: because alkaline metals (group IA metals) are the strongest reducing agents and most reactive metals.
Reducing agent is an element or compound that loses an electron to another chemical species in a redox chemical reaction and they have been oxidized.
Alkaline metals tend to lose only one electron in redox reaction.

5 0

3 years ago

PH is 7.45. Calculate value of [H3O+] and [OH-]

lana66690 [7]

Answer:

The answer is (H30+) =3,55e-8M and (OH-)=2,82e-7M

Explanation:

We use the formulas:

pH= - log(H30+) and Kwater=(H30+)x(OH-)

pH= - log(H30+) ----< (H30+)= antilog- pH=antilog- 7,45=3,55E-8M

Kwater=(H30+)x(OH-)

(OH-)=Kwater/(H30+)= 1,00e-14/3,55e-8 = 2,82e-7

8 0

3 years ago

A 0.0000792 M sample of Compound X in a solvent has an absorbance of 0.341 at 528 nm in a 1.000-cm cuvet. The solvent alone has

natima [27]

Answer:

a) a = 3485 M⁻¹cm⁻¹

b) C = 0,000127 M

Explanation:

Lambert-Beer law says that there is a linear relationship between absorbance and concentration of a chemical substance. The formula is:

A = a×b×C

Where A is absorbance, a is molar absorptivity, b is path length and C is concentration.

a) In the problem Concentration is 0.0000792 M, b is 1,000cm and Absorbance is absorbance of sample-absorbance of blank: 0,341-0,065 = 0,276

Replacing:

0,276 = a×1,000cm×0,0000792M

a = 3485 M⁻¹cm⁻¹

b) As the experiment consist in the same compound in the same solvent, the molar absorptivity will be the same, a = 3485 M⁻¹cm⁻¹, path length will be 1,000cm and absorbance: 0,508-0,065 = 0,443

Replacing:

0,443 = 3485 M⁻¹cm⁻¹×1,000cm×C

C = 0,000127 M

I hope it helps!

8 0

3 years ago