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Andru [333]
3 years ago
8

A partially inflated balloon is faded over the open end of a glass beaker that contains water the beaker is placed in an ice bat

h which cause the water and causes the balloon to the flea what are the correct designs for the heat and work changes to the beaker and balloon system

Physics
1 answer:
grin007 [14]3 years ago
7 0

Answer:

a

Explanation:

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Drag the tiles to the correct boxes to complete the pairs.
marishachu [46]

Answer:

Air pollution---> smog

Water pollution---> eutrophication

Land pollution---> contaminated soil

Light pollution---> sky glow

7 0
3 years ago
You can obtain a rough estimate of the size of a molecule by the following simple experiment. Let a droplet of oil spread out on
Marat540 [252]

Answer:

  • The diameter of the molecule of oil is 1.405 10 ^{-9} \ m

Explanation:

We define density as

\rho = \frac{mass}{volume}

So, the volume for our oil will be

volume = \frac{mass}{\rho}

volume = \frac{7.62 \ 10^{-7} \ kg}{ 912 \ \frac{kg}{m^3}  }

volume = \frac{7.62 \ 10^{-7} \ kg}{ 912 \ \frac{kg}{m^3}  }

volume = 8.355 \ 10 ^{-10} \ m^3

the volume for a cylinder with radius r and height h is

volume = \pi r^2 h

So, we can obtain the height of the droplet of oil as:

h = \frac{volume}{\pi r^2}

the radius is

r=43.5  \ cm = 0.435 \ m

h = 1.405 10 ^{-9} \ m^3

And this is the diameter of the oil molecule.

6 0
3 years ago
What role does team collaboration play in successfully planning a mission to Mars?
mihalych1998 [28]

Answer:it helps get everyone in the same page

Explanation:

This is important so everyone knows what they should be doing

4 0
3 years ago
A spring with a force constant of 5.3 n/m has a relaxed length of 2.60 m. when a mass is attached to the end of the spring and a
olganol [36]
This is the equation for elastic potential energy, where U is potential energy, x is the displacement of the end of the spring, and k is the spring constant. 
<span> U = (1/2)kx^2 
</span><span> U = (1/2)(5.3)(3.62-2.60)^2 
</span> U = <span> <span>2.75706 </span></span>J
6 0
3 years ago
A horizontal spring with spring constant 210 Nm is compressed by 20 cm and then used to launch a 250 g box across the floor. The
Damm [24]

Answer:

ugmd = 1/2 kx²

d = (1/2 kx²) / (ugm)

= (1/2 * 250 N/m * (0.2 m)²) / (0.23 * 9.81 m/s² * 0.3 kg)

= 7.4 m

ugmd = 1/2 mv²

v = √2ugd

= √(2(0.23)(9.81 m/s²)(7.4 m)

= 5.8 m/s

Explanation:

3 0
4 years ago
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