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oksian1 [2.3K]
1 year ago
7

11. Amy is in a car that is moving at a speed of 50 kilometers/hour. If she moves a total distance of

Physics
1 answer:
lukranit [14]1 year ago
7 0
4 hours and 36minutes
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A 2.26 kg book is dropped from a height 1.5m what is its acceleration
Arada [10]
The answer is 9.8 ms^-2, because there is only one force acting on the object so the acceleration will be numerically equal to the gravitational field strength.
4 0
3 years ago
Carlos conduce su automóvil a 70 Km/h, mientras que Luis maneja una camioneta a la misma velocidad
DIA [1.3K]

Answer:

shsissjsisjuai

Explanation:

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4 0
3 years ago
Neglecting air​ resistance, the distance s left parenthesis t right parenthesis in feet traveled by a freely falling object is g
ivann1987 [24]

Explanation:

It is given that, the height of a certain tower is 862 feet i.e to reach on the ground the object should travel, s = 862 feet

The distance traveled by a freely falling object is given by :

s(t)=16t^2

16t^2=862

t=\sqrt{53.875}

t = 7.34 seconds

So, the object will take 7.34 seconds to fall to the ground from the top of the​ building. Hence, this is the required solution.

7 0
2 years ago
When we look into the sky every day we get to see the results of all the behaviors of waves. The blue color of the sky results f
mr_godi [17]

Answer:

λ = 0.4 x 10⁻⁶ m = 400 nm

Explanation:

The relationship between frequency, wavelength and speed of an electromagnetic wave is given as follows:

c = f\lambda

where,

c = speed of light = 3 x 10⁸ m/s

f = frequency of the light wave = 7.5 x 10¹⁴ Hz

λ = wavelength of the light = ?

Therefore,

3\ x\ 10^8\ m/s = (7.5\ x\ 10^{14}\ Hz)\lambda\\\\\lambda = \frac{3\ x\ 10^8\ m/s}{7.5\ x\ 10^{14}\ Hz}

<u>λ = 0.4 x 10⁻⁶ m = 400 nm</u>

4 0
3 years ago
A 16000 kg railroad car travels along on a level frictionless track with a constant speed of 23.0 m/s. A 5400 kg additional load
Alisiya [41]

Answer:

The speed of the car when load is dropped in it is 17.19 m/s.

Explanation:

It is given that,

Mass of the railroad car, m₁ = 16000 kg

Speed of the railroad car, v₁ = 23 m/s

Mass of additional load, m₂ = 5400 kg

The additional load is dropped onto the car. Let v will be its speed. On applying the conservation of momentum as :

m_1v_1=(m_1+m_2)v

v=\dfrac{m_1v_1}{m_1+m_2}

v=\dfrac{16000\ kg\times 23\ m/s}{(16000+5400)\ kg}

v = 17.19 m/s

So, the speed of the car when load is dropped in it is 17.19 m/s. Hence, this is the required solution.

6 0
3 years ago
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