Answer:
Energy use by bulb = 36 kJ
Explanation:
Power of bulb = 120 W
Time of working = 5 minutes =5 x 60 = 300 seconds.
Power = Work / Time
Work = Power x Time
= 120 x 300
= 36000 J = 36 kJ
So. energy use by bulb = 36 kJ
The motor in the platform works for W=1885J during this process.
<h3>What is joules?</h3>
The amount of energy expended when a force of one newton is applied across a displacement of one meter is known as a joule. A joule is equal to one watt of electricity emitted or lost over the course of one second. The British thermal unit (Btu) is sometimes used to express energy. the work- or energy-measurement unit derived from the SI. The energy required to accelerate a body with a mass of one kilogram over a distance of one meter using one newton of force is equal to one joule. Additionally, one joule is equal to one watt-second.
<h3>What is joules formula?</h3>
The energy required to exert one newton of force through one meter is measured in joules. For instance, the energy required to lift a one-kilogram object one meter is given by E = Fd = (ma)d = mgd = (1 kg)(9.8m/s2)(1 m) = 9.8 kg m/s2 = 9.8 joules.
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Answer:
Kinetic energy is the energy of motion
Answer:
Conditions that result in the emission of electrons from a conductor:
Heating the conductor to a suitable temperature
Exposing the conductor to a strong light
Subjecting the conductor to a very high applied voltage
Subjecting the conductor to high-speed electrons from another source
Both diodes and triodes influence current flow and contain electrodes. Diodes involve only two active pieces; triodes contain three electrodes within a tube. Current can flow through a diode in only one direction. Diodes tend to act as rectifiers. In a triode, the third electrode is a grid located between the cathode and the anode. A small difference of potential between the grid and the cathode controls the number of electrons that reach the anode. Adjusting the charge on the grid affects the number of electrons that can reach the anode. Triodes tend to act as amplifiers.
Transmitting antenna
Modulator
Oscillator
Microphone
RF amplifier
Receiving antenna
Loudspeaker
Demodulator
Tuner
hue, saturation, intensity/brightness
red, blue, green
Explanation:
Penn Foster
Answer:
700 mL or 0.0007 m³
Explanation:
P₁ = Initial pressure = 2 atm
V₁ = Initial volume = 350 mL
P₂ = Final pressure = 1 atm
V₂ = Final volume
Here the temperature remains constant. So, Boyle's law can be applied here.
P₁V₁ = P₂V₂
So, volume of this sample of gas at standard atmospheric pressure would be 700 mL or 0.0007 m³
