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3 years ago

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During resistance exercise, muscles are __________. A. working against a force B. repeatedly contracted C. concerted in movement

D. all of the aboveImproving muscular strength and endurance slows bone density loss.

1 answer:

ExtremeBDS [4]3 years ago

3 0

Answer:

the answer is A. working against a force

Explanation:

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A 16.2 kg person climbs up a uniform ladder with negligible mass. The upper end of the ladder rests on a frictionless wall. The

S_A_V [24]

To solve this problem we will apply the concepts related to the balance of forces. We will decompose the forces in the vertical and horizontal sense, and at the same time, we will perform summation of torques to eliminate some variables and obtain a system of equations that allow us to obtain the angle.

The forces in the vertical direction would be,

$\sum F_x = 0$

$f-N_w = 0$

$N_w = f$

The forces in the horizontal direction would be,

$\sum F_y = 0$

$N_f -W =0$

$N_f = W$

The sum of Torques at equilibrium,

$\sum \tau = 0$

$Wdcos\theta - N_wLsin\theta = 0$

$WdCos\theta = fLSin\theta$

$f = \frac{Wd}{Ltan\theta}$

The maximum friction force would be equivalent to the coefficient of friction by the person, but at the same time to the expression previously found, therefore

$f_{max} = \mu W=\frac{Wd}{Ltan\theta}$

$\theta = tan^{-1} (\frac{d}{\mu L})$

Replacing,

$\theta = tan^{-1} (\frac{0.9}{0.42*2})$

$\theta = 46.975\°$

Therefore the minimum angle that the person can reach is 46.9°

8 0

3 years ago

Hello, I want to ask. . anyone knows the answer.

stealth61 [152]

I would say D. because you round to the nearest whole number and 0.04 is way less than 0.5 which is a good rounding up number.

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3 years ago

Describe a situation where you could properly conclude that a set of data is precise but

Orlov [11]

It’s not arrested because if you look closer it’s plug walk I don’t even understand how it talk tho

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3 years ago

A hydraulic lift has two connected pistons with cross-sectional areas 15 cm2 and 670 cm2. It is filled with oil of density 510 k

BigorU [14]

Answer:

Explanation:

Given

Cross-sectional area of two areas is

$A_1=15\ cm^2$

$A_2=670\ cm^2$

It is filled with oil of density $\rho _0=510\ kg/m^3$

mass of car place on Large area $M=1100\ kg$

Suppose a mass of m kg is placed on smaller area

According to pascal law's intensity of pressure is same at every point on Liquid

$P_1=P_2$

$\frac{F_1}{A_1}=\frac{F_2}{A_2}$

$\frac{mg}{15}=\frac{Mg}{670}$

$m=1100\times \frac{15}{670}$

$m=24.62\ kg$

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3 years ago

Pay it forward! Answer a questio1) For a positive point charge, the lines radiate ………. . While, for a negative point charge, the

nikitadnepr [17]

Explanation:

1) For a positive point charge, the lines radiate outwards

for a negative point charge, the lines converge inwards

2) F = 2.3 X 10^-26 N

k = 9 X 10^9 N.m²/C

q1 = q2 = e = 1.6 X 10^-19 C

r = ?

F = kq1q2/r²

r² = kq1q2/F

r = √[kq1q2/F ]

r = √0.0100

r = 0.10m

The two protons are 0.10 m apart

3) The unit if electric field intensity is Newton-per-coulomb N/C

7 0

3 years ago