Answer:
1.1 m/s²
Explanation:
From the question,
F -mgμ = ma.................... Equation 1
Where F = applied force, m = mass of the apple cart, g = acceleration due to gravity, μ = coefficient of friction., a = acceleration of the apple cart.
Given: F = 115 N, m = 25 kg, μ = 0.35
Constant: g = 10 m/s²
Substitute these values into equation 2
115-(25×10×0.35) = 25×a
115-87.5 = 25a
25a = 27.5
a = 27.5/25
a = 1.1 m/s²
Answer:
Vf=3
Explanation:
you must first write your data
data before impact
M1=1000 M2=5000
V1=0 m/s V2 =0m/s
data after impact
M1=1000 M2=5000
V1=15m/s V2=?
M1V1 +M2V2=M1V1 +M2V2f
(1000)(0)+(5000)(0)=(1000)(15)+(5000)Vf
0=15000+5000Vf
- 15000÷5000=5000Vf÷5000
Vf= -3
Vf =3
Gravity increased the downward speed (or decreases the upward speed) by 9.8 m/s every second.
21.2/9.8 = 2.2 seconds
