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3 years ago

13

As energy transformations occur within a system, the total energy of the system it A)increases B) decreases C) remains constant

D) is transferred out of the system 2

1 answer:

fenix001 [56]3 years ago

4 0

C) remains constant
you could’ve used google smh

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5. A car accelerates from 0 to 72 km/hour in 8.0 seconds. What is the car's acceleration?

MA_775_DIABLO [31]

Answer:

2.5 m/s

Explanation:

There are calculators online that can help you easily calculate the accerlation.

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2 years ago

Find the magnitude of the average force ⟨Fx⟩⟨Fx⟩ in the x direction that the particle exerts on the right-hand wall of the conta

hodyreva [135]

Answer:

See explaination

Explanation:

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The attached file has a detailed solution of the given problem.

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3 years ago

Water is pumped steadily out of a flooded basement at a speed of 5.4 m/s through a uniform hose of radius 0.83 cm. The hose pass

Gala2k [10]

To solve this problem it is necessary to apply the concepts related to the flow as a function of the volume in a certain time, as well as the potential and kinetic energy that act on the pump and the fluid.

The work done would be defined as

$\Delta W = \Delta PE + \Delta KE$

Where,

PE = Potential Energy

KE = Kinetic Energy

$\Delta W = (\Delta m)gh+\frac{1}{2}(\Delta m)v^2$

Where,

m = Mass

g = Gravitational energy

h = Height

v = Velocity

Considering power as the change of energy as a function of time we will then have to

$P = \frac{\Delta W}{\Delta t}$

$P = \frac{\Delta m}{\Delta t}(gh+\frac{1}{2}v^2)$

The rate of mass flow is,

$\frac{\Delta m}{\Delta t} = \rho_w Av$

Where,

$\rho_w$ = Density of water

A = Area of the hose $\rightarrow A=\pi r^2$

The given radius is 0.83cm or $0.83 * 10^{-2}$ m, so the Area would be

$A = \pi (0.83*10^{-2})^2$

$A = 0.0002164m^2$

We have then that,

$\frac{\Delta m}{\Delta t} = \rho_w Av$

$\frac{\Delta m}{\Delta t} = (1000)(0.0002164)(5.4)$

$\frac{\Delta m}{\Delta t} = 1.16856kg/s$

Final the power of the pump would be,

$P = \frac{\Delta m}{\Delta t}(gh+\frac{1}{2}v^2)$

$P = (1.16856)((9.8)(3.5)+\frac{1}{2}5.4^2)$

$P = 57.1192W$

Therefore the power of the pump is 57.11W

6 0

3 years ago

Please any one have a clue on this one? Really need help on this

lana66690 [7]

Oxygen and Neon have the same number of valence electrons because both the compounds are in the same group and the outer orbital of both the compounds consists of 6 electrons

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3 years ago

6. A student notices that when a weight is hung on a spring, the spring stretches. She decides conduct an experiment to determin

natima [27]

Answer:

D

Explanation:

She says that the object of the experiment is to see how far the string stretches given a mass attached to the string.

The only thing that is at issue is either the mass or the amount the string stretches.

Nothing else matters.

The dependent variable therefore is the amount the string stretches. So the last choice is the answer.

4 0

2 years ago