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2 years ago

13

As energy transformations occur within a system, the total energy of the system it A)increases B) decreases C) remains constant

D) is transferred out of the system 2

1 answer:

fenix001 [56]2 years ago

4 0

C) remains constant
you could’ve used google smh

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the police department determined that the force required to drag a 130 N(29 lb) car tire across the pavement at a constant veloc

ki77a [65]

The force of friction is given by:
f = μR, where μ is the friction coefficient and R is the reaction force, which will be equal to the weight.
100 = μ x 130
μ = 0.77

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3 years ago

What is the mass of an object if a force of 2N and gives it an acceleration of 2 m/s2

tino4ka555 [31]

Answer:

1kg

Explanation:

Use the formula

F=ma

m=F/a

m=2N/2m/s^2

m=1kg

6 0

2 years ago

Answer for a thanks

mariarad [96]

Well, if your question is how light affects plants,

then you would want to design an experiment that plays aruond with the amount of light a plant gets

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2 years ago

According to Dalton’s atomic theory

NARA [144]

Dalton's atomic theory was the first complete attempt to describe all matter in terms of atoms and their properties. ... The first part of his theory states that all matter is made of atoms, which are indivisible. The second part of the theory says all atoms of a given element are identical in mass and properties.

6 0

2 years ago

A spring on Earth has a 0.500 kg mass suspended from one end and the mass is displaced by 0.3 m. What will the displacement of t

julia-pushkina [17]

To solve this problem we will apply the concepts related to the Force of gravity given by Newton's second law (which defines the weight of an object) and at the same time we will apply the Hooke relation that talks about the strength of a body in a system with spring.

The extension of the spring due to the weight of the object on Earth is 0.3m, then

$F_k = F_{W,E}$

$kx_1 = mg$

The extension of the spring due to the weight of the object on Moon is a value of $x_2$ , then

$kx_2 = mg_m$

Recall that gravity on the moon is a sixth of Earth's gravity.

$kx_2 = m\frac{g}{6}$

$kx_2 = \frac{1}{6} mg$

$kx_2 = \frac{1}{6} kx_1$

$x_2 = \frac{1}{6} x_1$

We have that the displacement at the earth was $x_1 = 0.3m$ , then

$x_2 = \frac{1}{6} 0.3$

$x_2 = 0.05m$

Therefore the displacement of the mass on the spring on Moon is 0.05m

6 0

2 years ago